Question

A knife is dropped from the top of a 10.0 m high mast on a ship moving at 1.74 m/s due south.

Answer 1

a)The velocity of the knife relative to the ship when it hits the deck of the ship will be 14.00 m/sec.

b)The velocity of the knife relative to a stationary observer on shore is 14.10 m/sec

c)The position at which the knife hits the deck is 82.8°.

What is velocity?

The change of displacement with respect to time is defined as speed. Speed is a scalar quantity. It is a time-based component. Its unit is m/sec.

The given data in the problem is;

The velocity of the knife relative to the ship when it hits the deck of the ship is;

v=√2gh

v=√2×9.81 ×10.0 m

v=14.00 m/sec

b)

The velocity of the knife relative to a stationary observer on shore is found as;

v₁₂ = √[(14.00)²+(1.74)²]

v₁₂=14.10 m/sec

c)

The position at which the knife hits the deck is;

$\rm \theta = tan^{-1}\frac{14.00}{1.75} \\\\ \theta = 82.8 ^ 0$

Hence, the velocity of the knife relative to the ship, the velocity of the knife relative to a stationary observer on shore, and the position at which the knife hits the deck will be 14.00 m/sec,14.10 m/sec, and 82.8° respectively.

To learn more about the velocity, refer to the link: brainly.com/question/862972.

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