A dog runs with an initial speed if 7.5m/s on a waxed floor. it slides to a stop in 15 seconds. What is the acceleration
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Answer:
Energy transferred = 28.8 Joules.
1. Energy transferred = 144 Joules.
2. The unit of potential difference, volts can also be described as Joules per Coulombs.
3. Current, I = 6.945 Amperes.
Explanation:
<u>Part A.</u>
Given the following data;
Current, I = 1.2A
Time, t = 2 minutes
Potential difference, V = 12 volts.
To find the energy transfered;
Energy transferred = charge moved * potential difference
E = Q * V
Substituting into the equation, we have;
Energy transferred = (1.2 * 2) * 12
Energy transferred = 2.4 * 12
Energy transferred = 28.8 Joules.
<u>Part B.</u>
1. <em><u>Given the following data;</u></em>
Charge, Q = 24C
Potential difference = 6V
To find the energy transferred;
E = Q * V
Substituting into the equation, we have;
E = 24 * 6
E = 144 Joules.
2. Since we know that, Energy transferred = charge moved * potential difference
The units of energy is Joules while the unit of the quantity of charge moved is Coulomb.
Therefore, the unit of potential difference becomes Joules per Coulomb.
3. <em><u>Given the following data;</u></em>
Potential difference = 18V
Energy transferred = 500J
Time, t = 4 minutes.
To find the current;
E = Q * V
Substituting into the equation, we have;
500 = Q*18
Q = 500/18
Q = 27.78C
But, Charge moved (Q) = current (I) * time (t)
Current, I = Q/t
Substituting into the equation, we have;
Current, I = 27.78/4
Current, I = 6.945 Amperes..
Answer:
1408.685 KN/C
Explanation:
Given:
R = 0.45 m
σ = 175 μC/m²
P is located a distance a = 0.75 m
k = 8.99*10^9
- The Electric Field Strength E of a uniformly solid disk of charge at distance a perpendicular to disk is given by:
part a)
Electric Field strength at point P: a = 0.75 m
part b)
Since, R >> a, we can approximate a / R = 0 ,
Hence, E simplified relation becomes:
E = σ / 2*e_o
part c)
Since, a >> R, we can approximate. that the uniform disc of charge becomes a single point charge:
Electric Field strength due to point charge is:
E = k*δ*pi*R^2 / a^2
Since, R << a, Surface area = δ*pi
Hence,
E = (k*δ*pi/a^2)