Question

A ball is thrown straight up with an initial speed of 30 m/s. How long will it take to reach the top of its trajectory, and high will the ball go?

Answer 1

Answer:

About 3.06 seconds

Explanation:

$v_f=v_o+at$

Since at the peak of its trajectory, the ball will have no velocity, you can write the following equation:

$0=30+(-9.81)t\\\\-30=-9.81t\\\\t\approx 3.06s$

Hope this helps!