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Anvisha [2.4K]
4 years ago
14

A ball is thrown straight up with an initial speed of 30 m/s. How long will it take to reach the top of its trajectory, and high

will the ball go?
Physics
1 answer:
stiv31 [10]4 years ago
8 0

Answer:

About 3.06 seconds

Explanation:

v_f=v_o+at

Since at the peak of its trajectory, the ball will have no velocity, you can write the following equation:

0=30+(-9.81)t\\\\-30=-9.81t\\\\t\approx 3.06s

Hope this helps!

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In the same configuration of the previous problem 3, four long straight wires are perpendicular to the page, and their cross sec
faust18 [17]

Complete Question:

In the same configuration of the previous problem 3, four long straight wires are perpendicular to the page, and their cross sections form a square of edge length a = 13.5 cm. Each wire carries 7.50 A, and the currents are out of the page in wires 1 and 4 and into the page in wires 2 and 3.

a) Draw a diagram in a (x,y) plane of the four wires with wire 4 perpendicular to the origin. Indicate the current's directions.

b) Draw a diagram of all magnetic fields produced at the position of wire 3 by the other three currents.

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Answer:

force, 1.318 ₓ 10⁻⁴

direction, 18.435°

Explanation:

The attached file gives a breakdown step by step solution to the questions

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3 years ago
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<u>Analysing the Question:</u>

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