Answer:
Probability of atleast one of 12 student has food allergies ≈ 0.58 ( approx)
Step-by-step explanation:
Given: Probability of a children under age 5 has food allergies = 7%
=![\frac{7}{100}](https://tex.z-dn.net/?f=%5Cfrac%7B7%7D%7B100%7D)
To find : Probability of atleast one of 12 student has food allergies
Probability of a chindren under age 5 does not have food allergies = ![1-\frac{7}{100}](https://tex.z-dn.net/?f=1-%5Cfrac%7B7%7D%7B100%7D)
⇒ prob = ![\frac{93}{100}](https://tex.z-dn.net/?f=%5Cfrac%7B93%7D%7B100%7D)
now we find Probability of atleast one of 12 student has food allergies this means we have to find prob of 1 student, 2 student, 3 student, till 12 student have allergy out of 12 student of class then add all prob.
But instead of finding all these probability we find probability of student having no allergy.i.e., 0 student then subtract it from 1(total probability)
Probability of 0 student having allergy out of 12 student = ![(\frac{93}{100})^{12}](https://tex.z-dn.net/?f=%28%5Cfrac%7B93%7D%7B100%7D%29%5E%7B12%7D)
Therefore, Probability of atleast one of 12 student has food allergies
= ![1-(\frac{93}{100})^{12}](https://tex.z-dn.net/?f=1-%28%5Cfrac%7B93%7D%7B100%7D%29%5E%7B12%7D)
= ![0.581403702521](https://tex.z-dn.net/?f=0.581403702521)
≈ 0.58 ( approx)
The answer is 26/7 it may seem to small to be the answer but just simplified it
Answer:
that looks hard sorry i cant help you good luk .
Answer:
V≈268.08cm³
Step-by-step explanation:
Hello there! If you know basic division, then you know that 8/2 is 4. With 75 calories being in 2 ounces of yogurt, all we have to do is multiply by 4 to get the amount of calories in 8 ounces of yogurt, because 2 * 4 is 8. Plus for this scenario, whatever we do to one part, we must do to the other. Let's solve. 75 * 4 is 300. There. There are 300 calories in 8 ounces of yogurt.