Hey there!
2(p + 1) + 8(p - 1) = 5p
2(p) + 2(1) + 8(p) + 8(-1) = 5p
2p + 2 + 8p - 8 = 5p
10p - 6 = 5p
SUBTRACT 5p to BOTH SIDES
10p - 6 - 5p = 5p - 5p
SIMPLIFY IT!
5p - 6 = 0
ADD 6 to BOTH SIDES
5p - 6 + 6 = 0 + 6
CANCEL out: -6 + 6 because it gives you 0
KEEP: 0 + 6 because it helps solve for the p-value
5p = 0 + 6
5p = 6
DIVIDE 5 to BOTH SIDES
5p/5 = 6/5
CANCEL out: 5/5 because it gives you 1
KEEP: 6/5 because gives you the result of the p-value
SIMPLIFY IT!
p = 6/5
Therefore, your answer is: p = 6/5
Good luck on your assignment and enjoy your day!
~Amphitrite1040:)
Note that x² + 2x + 3 = x² + x + 3 + x. So your integrand can be written as
<span>(x² + x + 3 + x)/(x² + x + 3) = 1 + x/(x² + x + 3). </span>
<span>Next, complete the square. </span>
<span>x² + x + 3 = x² + x + 1/4 + 11/4 = (x + 1/2)² + (√(11)/2)² </span>
<span>Also, for the x in the numerator </span>
<span>x = x + 1/2 - 1/2. </span>
<span>So </span>
<span>(x² + 2x + 3)/(x² + x + 3) = 1 + (x + 1/2)/[(x + 1/2)² + (√(11)/2)²] - 1/2/[(x + 1/2)² + (√(11)/2)²]. </span>
<span>Integrate term by term to get </span>
<span>∫ (x² + 2x + 3)/(x² + x + 3) dx = x + (1/2) ln(x² + x + 3) - (1/√(11)) arctan(2(x + 1/2)/√(11)) + C </span>
<span>b) Use the fact that ln(x) = 2 ln√(x). Then put u = √(x), du = 1/[2√(x)] dx. </span>
<span>∫ ln(x)/√(x) dx = 4 ∫ ln u du = 4 u ln(u) - u + C = 4√(x) ln√(x) - √(x) + C </span>
<span>= 2 √(x) ln(x) - √(x) + C. </span>
<span>c) There are different approaches to this. One is to multiply and divide by e^x, then use u = e^x. </span>
<span>∫ 1/(e^(-x) + e^x) dx = ∫ e^x/(1 + e^(2x)) dx = ∫ du/(1 + u²) = arctan(u) + C </span>
<span>= arctan(e^x) + C.</span>
His balance will be $6 because -19 - 35 = -54, he added 60 to the -54 so that makes 6 or $6
