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Marat540 [252]
3 years ago
7

Is the following statement true or false? A line is one-dimensional.

Mathematics
1 answer:
Mkey [24]3 years ago
3 0

Answer:

true

Step-by-step explanation:

A line is a straight one-dimensional figure having no thickness and extending infinitely in both directions. A line is sometimes called a straight line or, more archaically, a right line, to emphasize that it has no "wiggles" anywhere along its length.

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Solve for v.<br> -8v+3(v-3) = 16
puteri [66]

Hi there! :)

Answer:

\huge\boxed{v = -5}

-8v + 3(v - 3) = 16

Distribute the 3:

-8v + 3(v) + 3(-3) = 16

-8v + 3v - 9 = 16

Combine like terms and simplify:

-5v - 9 = 16

-5v - 9 + 9 = 16 + 9

-5v = 25

Divide both sides by -5:

-5v/(-5) = 25/(-5)

v = -5.

7 0
3 years ago
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Simplify (2m^6)^3.
labwork [276]

Answer:

B. 8m ^ 18

Step-by-step explanation:

(2m ^6)^3 is the same as ;

(2 ^1 × m ^ 6) ^ 3.....multiply the powers 1 and 6 by 3

2 ^ (1×3) × m ^ (6×3).....this equals;

2 ^ 3 × m ^ 18

8m^18

hope this helps :)

8 0
3 years ago
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13.4×0.05×1.8= I think I got this right just wanna,make sure
andrew-mc [135]

Answer:1.206 is what i got


Step-by-step explanation:


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3 years ago
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During one snowy month a kentucky school held classes 9/11 of possible the school days if there are 22 possible school days how
SOVA2 [1]
This question isn't phrased correctly, but I will assume it's asking about common denominators with fractions.

9/11 1/22

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18 school days.
5 0
3 years ago
If a+b+c=0 then find the value of a^2+b^2+c^2/a^2-bc pls help me
VladimirAG [237]

a+b+c=0

[(a+b+c)^2=a^2+b^2+c^2+2ab+2ac+2bc]

[a^2+b^2+c^2+2ab+2ac+2bc=0]

[a^2+b^2+c^2=-(2ab+2ac+2bc)]

[a^2+b^2+c^2=-2(ab+ac+bc)] (i)

also

[a=-b-c]

[a^2=-ab-ac] (ii)

[-c=a+b]

[-bc=ab+b^2] (iii)

adding (ii) and (iii) ,we have

[a^2-bc=b^2-ac] (iv)

devide (i) by (iv)

[(a^2+b^2+c^2)/(a^2-bc)=(-2(ab+bc+ca))/(b^2-ac)]
8 0
3 years ago
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