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2 years ago

I need help asap it’s due today

Physics

1 answer:

jolli1 [7]2 years ago

6 0

For this experiment on a solar collector, the variables include the following:

Time

Temperature

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<h3>What are the variables?</h3>

In Science, a variable can be defined as a measurable attribute or physical quantity that changes or varies across an experiment and as such can take on different numerical values.

For this experiment on a solar collector, there are different variables and these include the following:

Time

Temperature

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Furthermore, you should determine both the greatest and smallest rate of temperature change for each of the trials by subtracting the initial temperature from the final temperature based on the numerical values obtained from this experiment.

In conclusion, the trial with the greatest numerical value has the greatest rate of temperature change while the trial with the smallest numerical value has the smallest rate of temperature change

Read more on variables here: brainly.com/question/632913

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<u>Complete Question:</u>

1. What are the variables in this investigation?

2. Which trial had the greatest rate of temperature change?

3. Which trial had the smallest rate of temperature change?

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A 5g block rests on a rough horizontal table a rope attached to the block is pulled with a force of 11N to the left as a result

mr Goodwill [35]

<u>Complete Question:</u>

A 5 g block rests on a rough horizontal table. A rope is attached to the block and is pulled with a force of 11 N to the left. As a result, the block accelerates at 2 m/s^2. What is the kinetic friction between the block and the table?

<u>Correct Answer:</u>

The kinetic frictional force between the block and the rough surface is 10.99 N towards the right side.

$F_{net}$ = - 0.01 N is the resulting net force causing an acceleration of $2\ m/s^2$ to the left

<u>Explanation:</u>

According to the first law of motion by Newton, any object can be moved only when an unbalanced force acts on the object. As the block is placed on a rough horizontal table, then the applied force should be greater than the kinetic frictional force between the object and the rough surface, in order to move that block.

So, it is known that the net force acting on the block will be the difference between the force acting on the object due to the rope and the frictional force acting on the object.

$F_{net} = F_{rope} -F_{friction}$

So, the force acting on the block due to rope is given as 11 N. The net force should be equal to the product of mass and acceleration of the object, as per Newton's second law of motion. As the mass of the block is 5 g and the acceleration is given as $2\ m/s^2$ .

$F_{net} = Mass * Acceleration = \frac{5}{1000} * -2 = -0.01 N$

Since, the net force and the force due to rope is acting opposite to the gravitational force ,

-0.01 = -11 - Frictional force

Frictional force = -11 + 0.01 = -10.99 N

Thus, the kinetic frictional force between the block and the rough surface is 10.99 N towards the right side.

$F_{net}$ = - 0.01 N is the resulting net force causing an acceleration of $2\ m/s^2$ to the left

7 0

3 years ago

Please help me on this quickly

skelet666 [1.2K]

Answer:

Explanation:

basic knowledge on properties of different forms of matter

3 0

3 years ago

Which type of bond is found between the atoms of a molecule?

Brrunno [24]

Answer:

Covalent Bond is found between the atoms of a molecule.

4 0

3 years ago

The International Space Station (ISS) orbits Earth in a nearly circular orbit that is 345 km above Earth's surface.

Tems11 [23]

Answer:

1) v = 7.70 10³ m/s , 2) F = 115 N and 3) (F/W)% = 90.2%

Explanation:

1) To solve the problem let's use Newton's second law where force is gravitational force and acceleration is centripetal

F = ma.

F = G m M / r²

a = v² / r

G m M / r² = m v² / r

G M / r = v²

Let's look for the distance is the distance from the surface of the has to the station 345 103 m plus the radius of the Earth

r = Re + 345 103

r = 6.37 10⁶ + 3.45 10⁵

r = 6.715 10⁶ m

Let's calculate the speed

v = √ (6.67 10⁻¹¹ 5.98 10²⁴ / 6,715 10⁶) = √ (59,399 10⁶)

v = 7.70 10³ m/s

The speed module is constant, so we can use the uniform motion relationships

v = d / t

The distance is the length of the circle

d = 2π r

d = 2π 6.715 106

d = 42.2 10⁶ m

Let's calculate the time

t = d / v

t = 42.2 10⁶ / 7.70 10³

t = 5.48 10³ s

2) Let's use the universal gravitation equation

F = G m M / r²

F = 6.67 10⁻¹¹ 13.0 5.98 10²⁴ /(6.715 10⁶)²

F = 11.5 10¹ N

F = 115 N

3) in this for we are asked the relationship is out with the weight of the body on earth

F / W = F / mg

F / W = 115 / (13.0 9.8)

F / W = 0.902

F / W% = 90.2%

5 0

3 years ago

How is Force helpful to us and how is harmful to us?

Oksana_A [137]

It makes objects stop and sometimes when too much force is applied to something, bad things happen.

6 0

3 years ago