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3 years ago

Which of the following statements DOES NOT explicitly describe a transfer of money

Physics

2 answers:

Naddik [55]3 years ago

6 0

Answer:

The correct answer is A.

Explanation:

A. A ball dropped from a heigh hits the ground with a high speed: This event does not produce any economic benefit.

B. The collision produced in a nuclear reaction heat up the surroundings: This process describes a heat transfer, which is used in nuclear reactors to produce energy, which translates into economic benefits.

C. An plane increases its air speed from 150 mi/hr to 200 mi/hr: In this case, the consumption of extra gasoline to increase the speed of the plane produces a loss of money.

D. The electricity from the power socket causes the fan to turn: Using an electrical appliance consumes current, which must be paid for and produces a waste of money.

Have a nice day!

kirill115 [55]3 years ago

3 0

I think it’s c bc people get paid to drive others around the world

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Kyle and Jenny both have pet rabbits. They wanted to see who had the fastest rabbit, so they each recorded data at their homes a

jekas [21]

Answer:

v_kyle = 0.5 m/s

v_jennies = 0.333 m/s

Kyle's Rabbit was the fastest

Explanation:

For the velocity of Kyle's Rabbit:

d = distance covered = 40 m

t = time taken = (1 min)(60s/1 min) + 20 s = 80 s

$v_{kyle} = \frac{d}{t} = \frac{40\ m}{80\ s}$

v_kyle = 0.5 m/s

For the velocity of Jennies Rabbit:

d = distance covered = 30 m

t = time taken = (1 min)(60s/1 min) + 30 s = 90 s

$v_{jennies} = \frac{d}{t} = \frac{30\ m}{90\ s}$

v_jennies = 0.333 m/s

It is clear from the results that:

Kyle's Rabbit was the fastest

7 0

3 years ago

Each time you dumped the pennies, one half-life passed; it has been shown that the half-life for this radioactive isotope is 20

tresset_1 [31]

The exponential decay function is shown as:

At = Ao*2^(-t/h)

Where:

At = Final amount
Ao = original amount
t = time
h = years for half-life to occur

We are not given the original and final amounts, but we are told that after the certain amount of time had passed, only 5% had remained. So if we were to isolate At and Ao in one side of the equation, such that: At/Ao = 0.05, we can solve for the missing variable, which is t.

Substituting:

At/Ao = 2^(-t/h)
0.05 = 2^(-t/20)
t = 86.44 years

Therefore, the pottery was made approximately 86.44 years ago.

3 0

3 years ago

Refer to the first diagram. What is the weight of the person hanging on the end of the seesaw in Newtons?

irina1246 [14]

Due to equilibrium of moments:

1) The weight of the person hanging on the left is 250 N

2) The 400 N person is 3 m from the fulcrum

3) The weight of the board is 200 N

Explanation:

To solve the problem, we use the principle of equilibrium of moments.

In fact, for the seesaw to be in equilibrium, the total clockwise moment must be equal to the total anticlockwise moment.

The moment of a force is defined as:

$M=Fd$

where

F is the magnitude of the force

d is the perpendicular distance of the force from the fulcrum

In the first diagram:

- The clockwise moment is due to the person on the right is

$M_c = W_2 d_2$

where $W_2 = 500 N$ is the weight of the person and $d_2 = 2 m$ is its distance from the fulcrum

- The anticlockwise moment due to the person hanging on the left is

$M_a = W_1 d_1$

where $W_1$ is his weight and $d_1 = 4 m$ is the distance from the fulcrum

Since the seesaw is in equilibrium,

$M_c = M_a$

So we can find the weight of the person on the left:

$W_1 d_1 = W_2 d_2\\W_1 = \frac{W_2 d_2}{d_1}=\frac{(500)(2)}{4}=250 N$

Again, for the seesaw to be in equilibrium, the total clockwise moment must be equal to the total anticlockwise moment.

- The clockwise moment due to the person on the right is

$M_c = W_2 d_2$

where $W_2 = 400 N$ is the weight of the person and $d_2$ is its distance from the fulcrum

- The anticlockwise moment due to the person on the left is

$M_a = W_1 d_1$

where $W_1 = 300 N$ is his weight and $d_1 = 4 m$ is the distance from the fulcrum.

Since the seesaw is in equilibrium,

$M_c = M_a$

So we can find the distance of the person on the right:

$W_1 d_1 = W_2 d_2\\d_2 = \frac{W_1 d_1}{W_2}=\frac{(300)(4)}{400}=3 m$

As before, for the seesaw to be in equilibrium, the total clockwise moment must be equal to the total anticlockwise moment.

- The clockwise moment around the fulcrum this time is due to the weight of the seesaw:

$M_c = W_2 d_2$

where $W_2$ is the weight of the seesaw and $d_2 = 3 m$ is the distance of its centre of mass from the fulcrum

- The anticlockwise moment due to the person on the left is

$M_a = W_1 d_1$

where $W_1 = 600 N$ is his weight and $d_1 = 1 m$ is the distance from the fulcrum

Since the seesaw is in equilibrium,

$M_c = M_a$

So we can find the weight of the seesaw:

$W_1 d_1 = W_2 d_2\\W_2 =\frac{W_1 d_1}{d_2}= \frac{(600)(1)}{3}=200 N$

#LearnwithBrainly

8 0

3 years ago

A 4.0 kg ball is traveling at 3.0 m/s and strikes a wall. The ball bounces off the wall with a velocity of 4.0 m/s in the opposi

trasher [3.6K]

Answer:

280 N

Explanation:

Applying Newton's third second law of motion,

F = m(v-u)/t................... Equation 1

Where F = Magnitude of the average force on the ball during contact, v = final velocity of the ball, u = initial velocity of the ball, t = time of contact of the ball and the wall.

Note: Let the direction of the initial velocity of the ball be positive

Given: m = 4 kg, u = 3.0 m/s, v = -4.0 m/s (bounce off), t = 0.1 s

Substitute into equation 1

F = 4(-4-3)/0.1

F = 4(-7)/0.1

F = -28/0.1

F = -280 N.

Note: The negative sign tells that the force on the ball act in opposite direction to the initial motion of the ball

3 0

3 years ago

The back wall of a home aquarium is a mirror that is a distance of 46.0 cm away from the front wall. The walls of the tank are n

monitta

Answer:

i know the questin but i got to try and find it

Explanation:

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3 years ago