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vovikov84 [41]
3 years ago
7

The age of the universe is around 100,000,000,000,000,000s. A top quark has a lifetime of roughly 0.000000000000000000000001s. W

riting numbers out with all these zeros is not very convenient. Such quantities are usually written as powers of 10. The age of the universe can be written as 1017s and the lifetime of a top quark as 10−24s.Note that1017 means the number you would get by multiplying 10 times 10 times 10... a total of 17 times. This number, as you can see above, would be a one followed by seventeen zeros. Similarly, 10−24 is the result of multiplying 0.1 (or 1/10) times itself 24 times. As seen above, this is written as 23 zeros after the decimal point followed by a one.***How many top quark lifetimes have there been in the history of the universe (i.e., what is the age of the universe divided by the lifetime of a top quark)? Note that these powers of 10 follow the same rules that any exponents would follow.
Physics
1 answer:
QveST [7]3 years ago
7 0

Answer:

10^{41}

Explanation:

Age of the universe = 100,000,000,000,000,000=10^{17}\ s

Lifetime of a top quark = 0.000000000000000000000001=10^{-24}

Top quark life would be given by

t=\dfrac{\text{Age of the universe}}{\text{Lifetime of a top quark}}\\\Rightarrow t=\dfrac{10^{17}}{10^{-24}}\\\Rightarrow t=10^{17+24}\\\Rightarrow t=10^{41}\ s

Hence, the answer is 10^{41}\ s

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Is the movement of wind kinetic energy ?
kari74 [83]

Answer: Well that is a good question and the answer is that wind energy is motion which is kinetic energy since its a renewable energy source.

Hope it helps

3 0
3 years ago
44. A mediados de la década de 1960, la McGill University lanzó sensores metereológicos de gran altitud al dispararlos desde un
Afina-wow [57]

La cinemática permite encontrar la respuesta para la aceleracion del cuerpo en el cañón es:

            a = 1,8 10⁶ m/s²  

 

La cinemática estudia el movimiento de los cuerpos, buscando relaciones entre la posicion, la velocidad y la aceleración.

       v² = v₀² + 2 a x

Donde v y v₀ son la velocidad actual e inicial, respectivamente, a es la aceleracion y x la distancia recorrida.

Indica que la longitud de cañon es x= 18 m la velocidad de  salida es  

            v= 29000 km/h ( \frac{1000m}{1 km} ) ( \frac{1h}{3600s} s) = 8,055,56 m/s.

La velocidad inicial del proyectil es cero.

            a = \frac{v^2}{2x}  

            a = \frac{ 8055.56^2}{2 \ 18}  

            a = 1,8 10⁶ m/s²  

En conclusión usando la cinemática podemos encontrarla respuesta para la aceleracion del cuerpo en el cañón es:

            a = 1,8 10⁶ m/s²  

Aprender mas aquí:  brainly.com/question/19793086

4 0
2 years ago
Multiple Intelligences :
vlada-n [284]

Answer:

all of the above

PLS MARK ME AS BRAINLIAST

8 0
3 years ago
A 2000 kg roller coaster is at the top of a loop with a radius of 24 m. If its speed is 18 m/s at this point, what force does it
levacccp [35]

Answer:

46620\ \text{N}

Explanation:

m = Mass of roller coaster = 2000 kg

r = Radius of loop = 24 m

v = Velocity of roller coaster = 18 m/s

g = Acceleration due to gravity = 9.81\ \text{m/s}^2

Normal force at the point will be

N-mg=\dfrac{mv^2}{r}\\\Rightarrow N=\dfrac{mv^2}{r}+mg\\\Rightarrow N=\dfrac{2000\times 18^2}{24}+2000\times 9.81\\\Rightarrow N=46620\ \text{N}

The force exerted on the track is 46620\ \text{N}.

8 0
3 years ago
Certain neutron stars (extremely dense stars) are believed to be rotating at about 1000 rev/s. If such a star has a radius of 14
Sever21 [200]

Answer:

minimum mass of the neutron star = 1.624 × 10^30 kg

Explanation:

For  a material to remain on the surface of a rapidly rotating neuron star, the magnitude oĺf the gravitational acceleration on the material must be equal to the magnitude of the centripetal acceleration of the rotating neuron star.

This can be represented by the explanations in the attached document.

minimum mass of the neutron star = 1.624 × 10^30 kg

8 0
3 years ago
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