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lozanna [386]
3 years ago
11

Pleaseeeehelppppppppp

Mathematics
1 answer:
Kitty [74]3 years ago
3 0

Answer:

x = 72.5

Step-by-step explanation:

half of the angle given, so 72.5 degrees.

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Simplify (4x^– 4)^– 3
jarptica [38.1K]

Answer:

1/64x^12

Step-by-step explanation:

3 0
3 years ago
Question 3<br> Find the equation of the line joining (-2,4) and (3,7)
otez555 [7]

Answer:

y = (3/5)x+26/5 or 5y = 3x+26

Step-by-step explanation:

Applying,

The equation of a line in two point form

(y₂-y₁)/(x₂-x₁) = (y-y₁)/(x-x₁)............... Equation 1

From the question,

Given: y₂ = 7, y₁ = 4, x₂ = 3, x₁ = -2

Substitute these values into equation 1

(7-4)/[3-(-2)] = (y-4)/(x+2)

3/5 = (y-4)/(x+2)

5(y-4) = 3(x+2)

5y-20 = 3x+6

5y = 3x+6+20

5y = 3x+26

y = (3/5)x+26/5

Hence the equation of the line is y = (3/5)x+26/5 or 5y = 3x+26

7 0
2 years ago
According to a study done by a university​ student, the probability a randomly selected individual will not cover his or her mou
Anon25 [30]

 Let X be a discrete binomial random variable.
 Let p = 0.267 be the probability that a person does not cover his mouth when sneezing.
 Let n = 18 be the number of independent tests.
 Let x be the number of successes.
 So, the probability that the 18 individuals, 8 do not cover their mouth after sneezing will be:

 a) P (X = 8) = 18! / (8! * 10!) * ((0.267) ^ 8) * ((1-0.267) ^ (18-8)).
 P (X = 8) = 0.0506.

 b) The probability that between 18 individuals observed at random less than 6 does not cover their mouth is:

 P (X = 5) + P (X = 4) + P (X = 3) + P (X = 2) + P (X = 1) + P (X = 0) = 0.6571.

 c) If it was surprising, according to the previous calculation, the probability that less than 6 people out of 18 do not cover their mouths is 66%. Which means it's less likely that more than half of people will not cover their mouths when they sneeze.
4 0
2 years ago
Find the probability of selecting none of the correct six integers in a lottery, where the order in which these integers are sel
serious [3.7K]

Complete Questions:

Find the probability of selecting none of the correct six integers in a lottery, where the order in which these integers are selected does not matter, from the positive integers not exceeding the given integers.

a. 40

b. 48

c. 56

d. 64

Answer:

a. 0.35

b. 0.43

c. 0.49

d. 0.54

Step-by-step explanation:

(a)

The objective is to find the probability of selecting none of the correct six integers from the positive integers not exceeding 40.  

Let s be the sample space of all integer not exceeding 40.

The total number of ways to select 6 numbers from 40 is |S| = C(40,6).

Let E be the event of selecting none of the correct six integers.

The total number of ways to select the 6 incorrect numbers from 34 numbers is:

|E| = C(34,6)

Thus, the probability of selecting none of the correct six integers, when the order in which they are selected does rot matter is  

P(E) = \frac{|E|}{|S|}

         = \frac{C(34, 6)}{C(40, 6)}\\\\= \frac{1344904}{3838380}\\\\=0.35

Therefore, the probability is 0.35

Check the attached files for additionals  

8 0
3 years ago
Choose the ratio you would use to convert 88 pounds to ounces remember that there are 16 ounces in 1 pound
natima [27]
Your answer would be B. 16 ounces/1 pound
5 0
3 years ago
Read 2 more answers
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