The value of x in x^yz = y^2 is ![x = \sqrt[yz]{y^2}](https://tex.z-dn.net/?f=x%20%3D%20%5Csqrt%5Byz%5D%7By%5E2%7D)
<h3>How to solve for x?</h3>
The equation is given as:
x^yz = y^2
Rewrite the equation properly as follows
Take the yz root of both sides
![\sqrt[yz]{x^{yz}} = \sqrt[yz]{y^2}](https://tex.z-dn.net/?f=%5Csqrt%5Byz%5D%7Bx%5E%7Byz%7D%7D%20%3D%20%5Csqrt%5Byz%5D%7By%5E2%7D)
Apply the law of indices
![x^{\frac{yz}{yz}} = \sqrt[yz]{y^2}](https://tex.z-dn.net/?f=x%5E%7B%5Cfrac%7Byz%7D%7Byz%7D%7D%20%3D%20%5Csqrt%5Byz%5D%7By%5E2%7D)
Divide yz by yz
Hence, the value of x in x^yz = y^2 is
Read more about equations at:
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5,125,000 because you divide the amount he has by 0.4 then yo multiply that by 10
Answer:
C
Step-by-step explanation:
For any given function, all first input values (x-values/coordinates) in the relation are considered as the domain values. While the output values (y-values/coordinates) make up the range of the given function.
The mapped relation that has a domain of {1,2,3}, is the mapped relation that has 1, 2, and 3 on the input side on our left.
Therefore, the mapped relation in option C is the answer.
G and b are the answers I think I will get more answers if I were you
