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goblinko [34]
2 years ago
9

A 0.65 M solution of an unknown amine base is found to be 2.2% ionized at equilibrium. Calculate the value for Kb for this amine

.
Chemistry
1 answer:
mihalych1998 [28]2 years ago
6 0

The value of Kb of the unknown amine is 3.22 x 10^-4.

Weak electrolytes:

The compound which do not dissociate completely when added to the aqueous solution are called weak electrolytes. The electrolyte and its ions exists in equilibrium. In case of weak base, the equilibrium constant is expressed as Kb.

Calculations:

Step 1:

The percentage of amine ionized at equilibrium is 2.2%.

NH3   +     H2O ------>    NH4+   +    OH-

The concentration of conjugate acid at equilibrium is calculated as:

2.2 = (x/0.65) x 100

x = 0.0143 M

Step 2:

The equilibrium constant (Kb) is calculated as:

Kb = x^2/0.65 - x

= (0.0143)^2/(0.65 - x)

= 3.22 x 10^-4

Learn more about weak electrolytes here:

brainly.com/question/19340043

#SPJ4

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