F(x) = 2x2 + 3x + 5,

A 25 ft. ladder resting against the side of a building forms a right triangle with the ground. The bottom of the ladder is 7 ft.

ruslelena [56]

Answer:

The correct answer is 24

Step-by-step explanation:

to solve this you will need to use the pathagreom theorum

a^{2}+b^{2}=c^{2}

A= one side lenth

B= the secons side lenth

C= hypotnuse

It is helpfull to draw out the situation

you know that the latter is 25 ft, that is your hypotnuse

you also know that the 7 ft away from the base of the building is one of the side lenths, lets call it side a

so plug the numbers into the equation

7^2 + b^2 = 25 ^2

you leave b^2 alone because that is the side you are trying to find

now square 7 and 25 but leave b^2 alone

49 + b^2 = 625

now subtract 49 from both sides

b^2 = 576

now to get rid of the square of b you have to do the opposite and square root both sides removing the square of the B and giving you the answer of..........

B= 24

Hope this helped!! I tryed to explain it as simpil as possiable

6 0

2 years ago

Read 2 more answers

Consider the equation y = 3x - 1. Identify the slope and y-intercept and

tatyana61 [14]

Answer: slope=3

y intercept :(0, -1)

Step-by-step explanation:Use the slope-intercept form to find the slope and y-intercept

4 0

3 years ago

I need Help!!! (Question is attached)

katrin2010 [14]

Answer:

SEE BELOW

Step-by-step explanation:

1 - 12000 ft

2 - 10 minutes

3 - The third segment in he graph is not as steep as the first segment because the flight took more time to lose altitude than the time taken to gain altitude.

Hope it helped

3 0

2 years ago

I need glow thank you appreciated

garri49 [273]

D bc it needs to have a y intercept of -1

4 0

3 years ago

Read 2 more answers

A ball is projected in to the air. Its height at time t is given by the equation

Ksju [112]

The equation gives the height of the ball. That is, h is the height of the ball. t is the time. Since we are looking for the time at which the height is 8 (h=8), we need to set the equation equal to 8 and solve for t. We do this as follows:

$h=-16 t^{2} +60t+1$
$8=-16 t^{2} +60t+1$
$16 t^{2} -60t-1+8=0$
$16 t^{2} -60t+7=0$

This is a quadratic equation and as it is set equal to 0 we can solve it using the quadratic formula. That formula is:
$t= \frac{-bplus minus \sqrt{ b^{2}-4ac } }{2a}$
You might recall seeing this as "x=..." but since our equation is in terms of t we use "t-=..."

In order to use the formula we need to identify a, b and c.
a = the coefficient (number in front of) $t^{2}$ = 16.
b = the coefficient of t = -60
c = the constant (the number that is by itself) = 7

Substituting these into the quadratic formula gives us:
$t= \frac{-(-60)plus minus \sqrt{ (-60)^{2}-4(16)(7) } }{2(16)}$
$t= \frac{60plus minus \sqrt{3600-448 } }{32}$
$t= \frac{60plus minus \sqrt{3152 } }{32}$

As we have "plus minus" (this is usually written in symbols with a plus sign over a minus sign) we split the equation in two and obtain:
$t= \frac{60+56.1426}{32} =3.63$
and
$t= \frac{60-56.1426}{32} =.12$

So the height is 8 feet at t = 3.63 and t=.12

It should make sense that there are two times. The ball goes up, reaches it's highest height and then comes back down. As such the height will be 8 at some point on the way up and also at some point on the way down.

3 0

3 years ago