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Natasha2012 [34]
2 years ago
9

4/5 + 2 /5 ÷ 2/ 3(they are fractions)PLEASE HURRY

Mathematics
1 answer:
chubhunter [2.5K]2 years ago
4 0

Answer:

1.4 or in fraction form 7/5

Step-by-step explanation:

Hope this is what you were looking for

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Please help me with this
I am Lyosha [343]

Answer:

The scale factor is 3

Step-by-step explanation:

The reason is that 12, 15, and 9 equal 4, 3, and 5 if divided by 3

7 0
2 years ago
How do I find the domain and range of a graph?​
tia_tia [17]

The domain is the x-axis and the range is the y-axis.

To find the domain, you measure or count the widest part of this oval horizontally. So that is 3 units to the right of 0 and 3 units to the left of 0. I counted it exactly on the axis because that is the widest part of the oval.

To find the range, you again count or measure the widest part of the oval vertically. So that is 4 units above 0 and 4 units below 0.

<u>Final Answer</u>

D: -3 ≤ x ≤ 3

R: -4 ≤ x ≤4

7 0
3 years ago
Help Plzzzzzzzzzzzzzzzzzzz
mars1129 [50]

(x+3)^{2}=19

7 0
2 years ago
A model of a car is 24 in. long. The actual car is 16 ft long. What is the ratio
kirill115 [55]

1 foot = 12 inches.

The model of the car is 24/12 = 2 feet long.

The ratio would be 2 ft/ 16 ft which can be reduced to 1/8

Answer 1/8

6 0
2 years ago
Read 2 more answers
An explained answer
Sholpan [36]

Answer:

  225

Step-by-step explanation:

When you fill in values of n, you find the series is an arithmetic series of 15 terms with a first term of 1 and a common difference of 2. The formula for the sum of such a series can be used.

<h3>Terms</h3>

Looking at terms of the series for different values of n, we find ...

  for n = 1: 2(1) -1 = 1 . . . . . the first term

  for n = 2: 2(2) -1 = 3 . . . . the second term; differs by 3-1=2

  for n = 15: 2(15) -1 = 29 . . . . the last of the 15 terms

<h3>Sum</h3>

The sum of the terms of an arithmetic series is the product of the average term and the number of terms. The average term is the average of the first and last terms.

  Sum = (1 +29)/2 × 15 . . . . . . average term × number of terms

  Sum = 15 × 15 = 225

The sum of the series is 225.

__

<em>Additional comment</em>

Based on the first term (a1), the common difference (d), and the number of terms (n), the sum can also be written ...

  S = (2×a1 +d(n -1))(n/2)

For the parameters of this series, the sum is ...

  S = (2(1) +2(15 -1))(15/2) = 30(15/2) = 225

5 0
1 year ago
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