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Viefleur [7K]
2 years ago
15

Marc mixes blue and yellow paint to make his favorite shade of green, which he'll use to paint his house. He has 14 cans of blue

paint and 20 cans of yellow paint when he starts.
He wants the same green color every time he mixes, so the amounts of blue and yellow must always be proportional to the original mixture.

On day 1, he mixes 4 cans of blue and 6 cans of yellow.
On day 2, he mixes 6 cans of blue and 9 cans of yellow.

Fill in the blanks to find the highest number of cans of each color Marc can mix to make the same shade of green on day 3.
Mathematics
1 answer:
exis [7]2 years ago
6 0

The ratio of blue paint to yellow paint is 2 : 3.

The total number of blue paint he used on the first and second day is 10.

The number of yellow paint he used on the first and second day is 15.

On the third day, the highest number of can of blue paint he can use is 2

On the third day, the highest number of can of yellow paint he can use is 3.

<h3>What is the highest number of blue and yellow paint he can use?</h3>

The ratio of blue paint to yellow paint can be determined by determining the simplest form of the paints used: 4 : 6 = 2: 3

Total blue paint cans used on the first and second day = 4 + 6 = 10

Blue paint cans remaining = 14 - 10 = 4

Total yellow paint cans used on the first and second day = 6 + 9 = 15 cans

Yellow paint cans remaining = 20 - 15 = 5 cans

Please find attached the questions. To learn more about ratios, please check: brainly.com/question/19711539

#SPJ1

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Find the value of the variable y, where the sum of the fraction 2/y-3 and 6/y+3 is equal to the quotient.
NISA [10]

Answer:

Here we need to solve:

\frac{2}{y - 3}  + \frac{6}{y + 3 }  = \frac{\frac{2}{y-3}}{\frac{6}{y + 3} }

The sum of the fractions is equal to the quotient between the fractions.

Notice that the two values:

y = 3

y = -3

make the denominator equal to zero, so those values are restricted.

We can simplify the right side to get:

\frac{2}{y - 3}  + \frac{6}{y + 3 }  = \frac{\frac{2}{y-3}}{\frac{6}{y + 3} } = \frac{2*(y + 3)}{6*(y - 3)}  = 3*\frac{y + 3}{y - 3}

Now we can multiply both sides by (y - 3)

(y - 3)*(\frac{2}{y - 3}  + \frac{6}{y + 3 }) = 3*(y + 3)\\2 + 6*\frac{y -3}{y + 3} = 3*(y + 3)

Now we can multiply both sides by (y + 3)

(2 + 6*\frac{y -3}{y + 3})*(y + 3) = 3*(y + 3)*(y + 3)

2*(y + 3) + 6*(y - 3) = 3*(y + 3)*(y + 3)\\\\2*y + 6 + 6*y - 18 = 3*(y^2 + 2*y*3 + 9)\\\\8*y - 12 = 3*y^2 + 6*y + 33\\\\0 = 3*y^2 + 6*y + 33 - 8*y + 12\\\\0 = 3*y^2 - 2*y + 45

First, let's see the determinant of that quadratic equation:

D = (-2)^2 - 4*3*45 = -536

We can see that it is negative, thus, there are no real solutions of the equation.

Thus, there is no value of y such that the origina equation is true,

6 0
3 years ago
Which of the following is a terminating decimal? Question 1 options:
Juli2301 [7.4K]
The answer for your question is c
6 0
3 years ago
A ball Is dropped from a height of 100'. The height of the ball can be determined using the equation h = -16t^2+ 100, Where H is
katen-ka-za [31]

Answer:

<h3>2.5secs</h3>

Step-by-step explanation:

Given the height of the ball modeled by the equation  h = -16t^2+ 100, where

h is the height

t is in seconds

We can find the time taken by the ball to reach the ground.

The ball reaches the ground when the height h = 0

Substitute h = 0 into the equation and find t;

0 = -16t^2+ 100

16t^2 = 100

t^2 = 100/16

t = √100/16

t = 10/4

t = 2.5secs

Hence the ball reaches the ground after 2.5secs

6 0
3 years ago
Which value of c would make the following express completely factored? 8x+cy
Artist 52 [7]
The answer is B, 7.

\sf 8x+2y

We can factor a 2 out of this: \sf 2(4x+y)

\boxed{\sf 8x+7y}

We can't factor anything.

\sf 8x+12y

We can factor a 4 out of this: \sf 4(2x+3y)

\sf 8x+16y

We can factor an 8 out of this: \sf 8(x+2y)

So your answer is B, 7.
6 0
3 years ago
Read 2 more answers
One pound of candies costs $3.50. How many pounds of candies can be bought for $10.50?
gregori [183]

Answer:

three pounds of Candie's can be bought for $10.50

3 0
3 years ago
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