Answer:
![\sf \Bigg[ \frac{ ( - 4 \times ( - 3)) }{2} \Bigg] \: and \: \Bigg[ \frac{ - ( - 5 \times 8)}{10} + 2 \Bigg]](https://tex.z-dn.net/?f=%20%20%20%5Csf%20%5CBigg%5B%20%5Cfrac%7B%20%28%20-%204%20%5Ctimes%20%28%20-%203%29%29%20%7D%7B2%7D%20%5CBigg%5D%20%5C%3A%20and%20%20%5C%3A%20%5CBigg%5B%20%5Cfrac%7B%20-%20%28%20-%205%20%5Ctimes%208%29%7D%7B10%7D%20%2B%202%20%5CBigg%5D)
Step-by-step explanation:
Given:
To find:
Two expressions that equal 6 using the given numbers
Solution:
Expression first,
Using numbers -4, 2, -3,
aligning the above numbers as,
will out put 6.
<em>Verification,</em>
Expression second,
Using numbers 10,8,2,-5
aligning the above numbers as,
will result 6.
<em>Verification</em>
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1/2r - 3 = 3(4-3/2) -----> Simplify the right side.
1/2r - 3 = 3(1/2) -----> Multiply
1/2r - 3 = 3/2 ----> Add 3 to both sides
1/2r = 6/2 + 3/2
1/2r = 9/2 -----> Divide both sides by 1/2 which is the same as multiplying my 2
r = 18/2
r = 9
Hope this helps!
Answer:
D is the answer.
Step-by-step explanation:
You can see if a line is perpendicular by the slope. If the slope is COMPLETELY opposite from another by means of slope, the lines are perpendicular.
-1/4
4/1
...are opposite.
The graph will cross at the coordinates (-2, 9)
<h3>How to solve equations?</h3>
y = 3x + 15
y = 3 - 3x
y = 3x + 15
Hence,
when x = 2
y = 3(2) + 15 = 21
when x = 0
y = 3(0) + 15 = 15
y = 3 - 3x
when x = 2
y = 3 - 3(2)
y = 3 - 6
y = -3
when x = 0
y = 3 - 3(0)
y = 3
Therefore, let's check if the equation will cross.
y = 3x + 15
y = 3 - 3x
using substitution,
3 - 3x = 3x + 15
3 - 15 = 3x + 3x
- 12 = 6x
x = -12 / 6
x = -2
y = 3 - 3(-2)
y = 3 + 6
y = 9
Therefore, the graph will cross at the coordinates (-2, 9)
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