Question

80% of people those who purchase pet insurance are women. If the owners of 9 pet insurance are randomly selected, then find the probability that exactly 6 out of them are women. Find the quartiles of the standard normal distribution.

Answer 1

The probability that exactly 6 out of them are women is 0.176

According to the statement

Number of selected pet owner randomly is 9. So, Here in this case n=9.(number of randomly selected owners).

Number for which have to find the probability is 6. So, Here in this case x=6.

Find the probability by a use of BINOMIAL THEOREM

So, n!/((n-x)!*x!) = 9!/((9-6)!*6!) = 84

Now, find out the probability of success p and probability of failure (1-p)=q.

From here we get p = 0.8 and q= 0.2

Now, use  p^x = (0.8)^6 = 0.2621

Then use q^(n-x) = (0.2)^(9-6) = 0.008

Now, Multiply the results obtained to get the probability is

84*0.2621*0.008 = 0.176

So, The probability that exactly 6 out of them are women is 0.176

Learn more about  probability here brainly.com/question/25870256

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