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weqwewe [10]
1 year ago
11

Why is it important to learn valid proportions ​

Mathematics
1 answer:
notsponge [240]1 year ago
6 0
<h3>Answer:</h3><h3>If you know one ratio in a proportion , you can use that information to find values in the other equivalent ratio. </h3>

You might be interested in
Simplify.<br><br> 15 20 24+20
WINSTONCH [101]

Answer:

-5 divide by 28

Step-by-step explanation:

so the question supposed be " 15-20 divided by 2(4) + 20

15-20 which is also 15 + (-20)= -5

2(4)=8, 8+20=28

so it can simplify into -5 / 28

(hope it helps :)

5 0
2 years ago
WILL GIVE BRAINLIEST
zloy xaker [14]

Answer:

Should be $300

let me know if it's correct:)

6 0
3 years ago
Read 2 more answers
Its my birthday soon, im turning 13 where would a fun place to go to
irinina [24]

Answer:

PAINTBALL

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
A solid is formed by adjoining two hemispheres to the ends of a right circular cylinder. An industrial tank of this shape must h
mestny [16]

Answer:

Radius =6.518 feet

Height = 26.074 feet

Step-by-step explanation:

The Volume of the Solid formed  = Volume of the two Hemisphere + Volume of the Cylinder

Volume of a Hemisphere  =\frac{2}{3}\pi r^3

Volume of a Cylinder =\pi r^2 h

Therefore:

The Volume of the Solid formed

=2(\frac{2}{3}\pi r^3)+\pi r^2 h\\\frac{4}{3}\pi r^3+\pi r^2 h=4640\\\pi r^2(\frac{4r}{3}+ h)=4640\\\frac{4r}{3}+ h =\frac{4640}{\pi r^2} \\h=\frac{4640}{\pi r^2}-\frac{4r}{3}

Area of the Hemisphere =2\pi r^2

Curved Surface Area of the Cylinder =2\pi rh

Total Surface Area=

2\pi r^2+2\pi r^2+2\pi rh\\=4\pi r^2+2\pi rh

Cost of the Hemispherical Ends  = 2 X  Cost of the surface area of the sides.

Therefore total Cost, C

=2(4\pi r^2)+2\pi rh\\C=8\pi r^2+2\pi rh

Recall: h=\frac{4640}{\pi r^2}-\frac{4r}{3}

Therefore:

C=8\pi r^2+2\pi r(\frac{4640}{\pi r^2}-\frac{4r}{3})\\C=8\pi r^2+\frac{9280}{r}-\frac{8\pi r^2}{3}\\C=\frac{9280}{r}+\frac{24\pi r^2-8\pi r^2}{3}\\C=\frac{9280}{r}+\frac{16\pi r^2}{3}\\C=\frac{27840+16\pi r^3}{3r}

The minimum cost occurs at the point where the derivative equals zero.

C^{'}=\frac{-27840+32\pi r^3}{3r^2}

When \:C^{'}=0

-27840+32\pi r^3=0\\27840=32\pi r^3\\r^3=27840 \div 32\pi=276.9296\\r=\sqrt[3]{276.9296} =6.518

Recall:

h=\frac{4640}{\pi r^2}-\frac{4r}{3}\\h=\frac{4640}{\pi*6.518^2}-\frac{4*6.518}{3}\\h=26.074 feet

Therefore, the dimensions that will minimize the cost are:

Radius =6.518 feet

Height = 26.074 feet

5 0
3 years ago
Please help!
Rus_ich [418]

Answer:

4

Step-by-step explanation:

I = PRT

252 = (900)(.07)(T)

252 = (63)(T)

divide 63 from both sides

4 = T

3 0
3 years ago
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