The first one is (1,10)
The second one is (1,5)
The third one is (0.5,10)
I hope this helps
Answer:
56
Step-by-step explanation:
If there can be only one 1 and only one 2, the remaining digits must all be 0. The digits 1 and 2 can be anywhere in the 8 digits, and can be in either order.
There are 8 possible locations in the sequence for the 1, then 7 possible locations for the 2. The total number of possibilities is 8·7 = 56.
12000000, 21000000, 10200000, 20100000, ..., 00000012, 00000021.
Answer:
if there is 40 passengers and 4 passengers per car there are 10 cars
Answer:
f(x)=33√x2(3x−16)xf(x)=3x23(3x-16)x
am not sure wait for the next answer sorry if it didn't help
is this for points cuz if it is then thank you :D
