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Ymorist [56]
2 years ago
12

Which of the following is the graph of y= e^x + 1?

Mathematics
1 answer:
Volgvan2 years ago
4 0

Answer + Step-by-step explanation:

y= e^x + 1

  • + 1 will shift the graph up 1
  • In the natural exponential function, eˣ = e power x, we employ e. In the eˣ function, the tangent line's slope to any point on the graph is equal to that point's y-coordinate. The sequence we employ to calculate the value of e is (1 + 1/n)

Learn more about Natural Exponential Functions here: brainly.com/question/1979778

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What is 2x + 3(x - 1) simplified?
maxonik [38]

Answer:

5x-3

Step-by-step explanation:

2x+3(x)+3(-1)= 2x+3x-3

5x-3

8 0
3 years ago
Hlep me pls daddddddddddddddddddddddddddddddddy
SashulF [63]

Answer:

The equation would be 2(n+3)-6. So A.

Step-by-step explanation:

It is asking you to subtract first and you cannot do that without  parentheses.

3 0
3 years ago
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Determine what type of model best fits the given situation:
lyudmila [28]

Let value intially be = P

Then it is decreased by 20 %.

So 20% of P = \frac{20}{100} \times P = 0.2P

So after 1 year value is decreased by 0.2P

so value after 1 year will be = P - 0.2P (as its decreased so we will subtract 0.2P from original value P) = 0.8P-------------------------------------(1)

Similarly for 2nd year, this value 0.8P will again be decreased by 20 %

so 20% of 0.8P = \frac{20}{100} \times 0.8P = (0.2)(0.8P)

So after 2 years value is decreased by (0.2)(0.8P)

so value after 2 years will be = 0.8P - 0.2(0.8P)

taking 0.8P common out we get 0.8P(1-0.2)

= 0.8P(0.8)

=P(0.8)^{2}-------------------------(2)

Similarly after 3 years, this value P(0.8)^{2} will again be decreased by 20 %

so 20% of P(0.8)^{2}  \frac{20}{100} \times P(0.8)^{2} = (0.2)P(0.8)^{2}

So after 3 years value is decreased by (0.2)P(0.8)^{2}

so value after 3 years will be = P(0.8)^{2}   - (0.2)P(0.8)^{2}

taking P(0.8)^{2} common out we get P(0.8)^{2}(1-0.2)

P(0.8)^{2}(0.8)

P(0.8)^{3}-----------------------(3)

so from (1), (2), (3) we can see the following pattern

value after 1 year is P(0.8) or P(0.8)^{1}

value after 2 years is P(0.8)^{2}

value after 3 years is P(0.8)^{3}

so value after x years will be P(0.8)^{x} ( whatever is the year, that is raised to power on 0.8)

So function is best described by exponential model

y = P(0.8)^{x} where y is the value after x years

so thats the final answer

3 0
3 years ago
On Monday, Noah finds 19 big grasshoppers and 9 small ones in his garden. What is the experimental probability of finding a smal
Lina20 [59]
That would be   9 /(19+9)   = 9/28 Answer
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Is it number 21 you need help with?
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