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Georgia [21]
3 years ago
6

How much does 3000 kg = to get tons

Mathematics
2 answers:
erastovalidia [21]3 years ago
8 0
Again
1000kg = 1ton
3000kg = 3 tons
Sloan [31]3 years ago
8 0
1 ton= 1000 kg
3000 kg= 3 ton
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Nitella [24]
With wat?
Yes


Step by step explanation
6 0
3 years ago
Read 2 more answers
A delivery truck is transporting boxes of two size: the combined weight of a large box and a small box is 65 pounds. The truck i
Bas_tet [7]

pretty much about the same as before.

a = weight of a large box

b = weight of a small box.

we know their combined weight is 65 lbs, thus a + b = 65.

we also know that the truck has 60 large ones, and 55 small ones, thus 60*a is the total weight for the large ones and 55*b is the total weight for the small ones, and we know that is a total of 3775, 60a + 55b = 3775.

\bf \begin{cases} a+b=65\\ \boxed{b}=65-a\\ \cline{1-1} 60a+55b=3775 \end{cases}\qquad \qquad \stackrel{\textit{substituting on the 2nd equation}}{60a+55\left( \boxed{65-a} \right)=3775} \\\\\\ 60a+3575-55a=3775\implies 5a+3575=3775\implies 5a=200 \\\\\\ a=\cfrac{200}{5}\implies \blacktriangleright a = 40 \blacktriangleleft \\\\\\ \stackrel{\textit{since we know that}}{b=65-a\implies }b=65-40\implies \blacktriangleright b=25\blacktriangleleft

6 0
4 years ago
Select the correct answer. 3 Twenty-seven minus 2 of a number (X) is not more than 36. What is the number? N O A. x > 42 OB.
e-lub [12.9K]

Answer:

the answer should be A.

Step-by-step explanation:

- College brother

3 0
3 years ago
What is the answer to 6-1x0+2/2 ?
Masja [62]
Answer is 6 you have to use distributive property to combine terms and than you simplify to get the answer<span />
6 0
3 years ago
4, Find a number x such that x = 1 mod 4, x 2 mod 7, and x 5 mod 9.
olchik [2.2K]

4, 7 and 9 are mutually coprime, so you can use the Chinese remainder theorem.

Start with

x=7\cdot9+4\cdot2\cdot9+4\cdot7\cdot5

Taken mod 4, the last two terms vanish and we're left with

x\equiv63\equiv64-1\equiv-1\equiv3\pmod4

We have 3^2\equiv9\equiv1\pmod4, so we can multiply the first term by 3 to guarantee that we end up with 1 mod 4.

x=7\cdot9\cdot3+4\cdot2\cdot9+4\cdot7\cdot5

Taken mod 7, the first and last terms vanish and we're left with

x\equiv72\equiv2\pmod7

which is what we want, so no adjustments needed here.

x=7\cdot9\cdot3+4\cdot2\cdot9+4\cdot7\cdot5

Taken mod 9, the first two terms vanish and we're left with

x\equiv140\equiv5\pmod9

so we don't need to make any adjustments here, and we end up with x=401.

By the Chinese remainder theorem, we find that any x such that

x\equiv401\pmod{4\cdot7\cdot9}\implies x\equiv149\pmod{252}

is a solution to this system, i.e. x=149+252n for any integer n, the smallest and positive of which is 149.

3 0
3 years ago
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