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3 years ago

12

I reallyyyyyyyyyyy need help!

1 answer:

xeze [42]3 years ago

6 0

It lies in quadrant III. If we subtract 360 from 570, then we know that 570° is the same as 210°. Remember that quadrant I has 0-90, II had 90-180, III had 180-270, and IV has 270-360. Then, 570 lies in quadrant III because the corresponding angle, 210, lies in quadrant III between 180 and 270. Hope this helps. :)

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(4x3 + 3x2 - 30x - 10) ÷ (x -3)

pogonyaev

(12x+6x-30x-10)/(x-3)=
=(-12x-10)/(x-3)
=-12x*+36- 10x+30=
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5 0

3 years ago

The diameter of a circle is 13 cm. Find its area to the nearest tenth.

Tatiana [17]

Area= $\pi$ $r^{2}$

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= $\pi$ 42.25

answer= 42.25 $\pi$

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4 years ago

Which is the inverse of the function f(x)= x+3

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Answer is C
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$make \: x \: subject \: of \: the \: formula$
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4 0

3 years ago

After a parade, a group of volunteers is helping to pick up the trash along a 2-mile stretch of a road.The group decides to divi

ANTONII [103]

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~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~``

3 0

3 years ago

Solve the system of equations.

tino4ka555 [31]

<u>Answer:</u>

(2, 7) or (-6, 1)

<u>Step-by-step explanation:</u>

We are given two equations:

$y=x+5$ ; and

$y = x^2+5x-7$

Since y is the subject for both the equations so we can put the values of y equal to each other to get:

$x+5=x^2+5x-7$

$x^2+5x-x-7-5=0$

$x^2+4x-12=0$

Factorizing the expression to get:

$x^2-2x+6x-12=0$

$x(x-2)+6(x-2)=0$

$(x-2) (x+6) = 0$

$x=2, x= -6$

Putting x = 2 and x = -6 in any of the equations to get the values of y:

$y=x+5$

$y =2+5$

$y=7$

and

$y =(-6)+5$

$y=1$

Therefore, solution to these equation is (2, 7) or (-6, 1).

5 0

3 years ago

Read 2 more answers