Answer:
you saved $3.20
Step-by-step explanation:
16 x 20/100
16 x 0.2
= 3.20
so 16-3.20= 12.80
final price is 12.80
Answer:
The graph below models the value of a $20,000 car t years after it was purchased.
Value of Car
A graph titled Value of Car has years bbhvb ngc,jon the x-axis and Dollars on the y-axis. A line curves down and goes through points (0, 20,000), (4, 10,000), and (14, 2,000).
Which statement best describes why the value of the car is a function of the number of years since it was purchased?
Each car value, y, is associated with exactly one time, t.
Each time, t, is associated with exactly one car value, y.
The rate at which the car decreases in value is not constant.
There is no time, t, at which the value of the car is 0.
Step-by-step explanation:
Answer:
Atomic No.
Element
Atomic Wt.
Europium
To take a systematic sample, first choose any number between one and five and write it here: k-23
Using the atomic number to count off elements, let the k value you just chose represent the first element in your
sample. Then, count off every fifth element thereafter. For instance, if you chose k-2, your sample will include
Helium (2), Nitrogen (7), Magnesium (12), and so forth. List each atomic number and atomic weight, starting with k
and adding 5 to the atomic number cach time.
Atomic No. Element
Atomic Wt.
3. Lithium 6.94
63
Isla6
8
v४
16
oxygen
Erbium 167.26
13 nluminum 24.98 23 Tantalum
180.45
18 Argon
39.95
28
platinum
195.DK
23 Vanadium 50.94 83 Bismuth 208.48
Niin
28
86
158.69
Radium 226
33
Arsenic 74.92
93 Neptunium 237
38 Strontium
98
87.62
Californium 251
43 Technutium 98
103 Lawrencium 262
UR
cocaina [12.41
108
Hassium
277
Iodine 126.9
113
No element
o
658 Cerium 140:11 118 Unumactiun
63
294
Find the mean atomic weight of this sample and enter it here: x xytomate : 137
AP statistics
Step-by-step explanation:
Sum of a number, x and 4 all divided by 3
sum of x and 4 means x+4
all divided by 3

evaluate for x=5



it's 3
Answer:
8hr=480min
30min=1800sec
15hr=900min
5yr=1825d
Step-by-step explanation: