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alexgriva [62]
3 years ago
6

Can u plz help meh with this 6th grade math. U have to write an algebraic equation and solve. Only solve 2, 3, 4, 7, 8. Thank Yo

u!!!

Mathematics
1 answer:
ra1l [238]3 years ago
3 0
2. 24-7p=10
-7p=-14
p=2

3. x+(x+1)+(x+2)=72
3x+3=72
3x=69
x=23

4. x+(x+2)+(x+4)=48
3x+6=48
3x=42
x=14

7. 40-2x=8
-2x=-32
x=16

8. 1/2x+4=12
1/2x=8
x=16
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F(x) = x2 + 4x − 6
german

Since

x^2+4x+4=(x+2)^2

Is a perfect square, we can think of the "-6" at the end as a "+4-10" and we have

x^2+4x-6 = x^2+4x+4-10 = (x+2)^2-10

Which is the required form

6 0
4 years ago
In a recipe, the ratio of fluid ounces of water to fluid ounces of tomato paste is 3:4. You plan to make 35 fluid ounces of sauc
WITCHER [35]
3:4......added = 7

3/7(35) = 105/7 = 15 oz water
4/7(35) = 140/7 = 20 oz tomato paste <==
4 0
3 years ago
What is the range of the relation, {(2, 8) (-3, -1) (4, -7) (5, 0) (-1, 2)}? create the range for the relation.
ivanzaharov [21]

The range is all the second values or ys

[-7, -1, 0, 2, 8]  


5 0
3 years ago
Terri Vogel, an amateur motorcycle racer, averages 129.71 seconds per 2.5 mile lap (in a 7 lap race) with a standard deviation o
Vikki [24]

Answer:

(a) The percent of her laps that are completed in less than 130 seconds is 55%.

(b) The fastest 3% of her laps are under 125.42 seconds.

(c) The middle 80% of her laps are from <u>126.80</u> seconds to <u>132.63</u> seconds.

Step-by-step explanation:

The random variable <em>X</em> is defined as the number of seconds for a randomly selected lap.

The random variable <em>X </em>is normally distributed with mean, <em>μ</em> = 129.71 seconds and standard deviation, <em>σ</em> = 2.28 seconds.

Thus, X\sim N(129.71,\ 2.28^{2}).

(a)

Compute the probability that a lap is completes in less than 130 seconds as follows:

P(X

                   =P(Z

The percentage is, 0.55 × 100 = 55%.

Thus, the percent of her laps that are completed in less than 130 seconds is 55%.

(b)

Let <em>x</em> represents the 3rd percentile.

That is, P (X < x) = 0.03.

⇒ P (Z < z) = 0.03

The value of <em>z</em> for the above probability is:

<em>z</em> = -1.88

Compute the value of <em>x</em> as follows:

z=\frac{x-\mu}{\sigma}\\-1.88=\frac{x-129.71}{2.28}\\x=129.71-(1.88\times 2.28)\\x=125.4236\\x\approx 125.42

Thus, the fastest 3% of her laps are under 125.42 seconds.

(c)

Let <em>x</em>₁ and <em>x</em>₂ be the values between which the middle 80% of the distribution lie.

That is,

P(x_{1}

The value of <em>z</em> for the above probability is:

<em>z</em> = 1.28

Compute the values of <em>x</em>₁ and <em>x</em>₂ as follows:

-z=\frac{x_{1}-\mu}{\sigma}\\-1.28=\frac{x_{1}-129.71}{2.28}\\x_{1}=129.71-(1.28\times 2.28)\\x=126.7916\\x\approx 126.80               z=\frac{x_{2}-\mu}{\sigma}\\1.28=\frac{x_{2}-129.71}{2.28}\\x_{2}=129.71+(1.28\times 2.28)\\x=132.6284\\x\approx 132.63

Thus, the middle 80% of her laps are from <u>126.80</u> seconds to <u>132.63</u> seconds.

5 0
3 years ago
What is the solution to the system of equations?
Trava [24]

Call the two equations above A and B, in order to not confuse them.

A: -2x + 6y = -38

B: 3x - 4y = 32

For this system we have opposites in x and y, so Elimination (or Linear Combination) works best. Either variable works, so let's work with x first and multiply A by 3 and B by 2. This is done so we get opposites in A and B then when added together give zero.

-2x + 6y = -38 ------> multiply by 3 ----> -6x + 18y = -114

3x - 4y = 32 ------> multiply by 2 -----> 6x - 8y = 64

Now we add the new equations. The -6x and 6x are opposites and go away. We are left with

10y = -50. We divide both sides by 10 and get that y = -5.

Now we take y = -5 and put it into an original equation. Let's use A.

-2x + 6y = -38 the original equation A

-2x + 6(-5) = -38 we found y = -5

-2x + (-30) = -38 evaluating and multiplying

-2x - 30 = -38 apply the parentheses

-2x = -8 add 30 to both sides

x = 4 divide on both sides by -2


Thus x = 4 and y = -5, or (4, -5) is the solution.

6 0
3 years ago
Read 2 more answers
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