Answer:
zero order reaction
Explanation:
The seem to be a reaction is zero order as the data only fits to zero order integrated rate law.
Integrated rate law:
[A] = [A]_0 – kt
Here y = [ A] and slope is -k , so when we plot concentration of A with respect to t then we get the equation in the form of line
y = mx + c
So the answer Zero order in [A]
Explanation:
Mole ratio of Oxygen to Hydrogen gas = 1 : 2.
If we use 3.0 moles of oxygen gas, we would need 3.0 * 2 = 6.0 mol of hydrogen gas.
However we only have 4.2 mol of hydrogen. Therefore hydrogen is limiting and oxygen is in excess. (B)
Answer:
Hydride ion
Explanation:
You often see the reduction with NADH written as
NADH ⟶ NAD⁺ + H⁺ + 2e⁻
If you think about it, H⁺ + 2e⁻ is equivalent to H:⁻, so we could write the reaction as
NADH ⟶ NAD⁺ + H:⁻
In terms of a mechanism, the dihydropyridine ring of NADH transfers a hydrogen atom with its pair of electrons (a hydride ion) to the substrate and becomes the more stable, aromatic pyridinium ion in NAD⁺.
I'm guessing water vapour. i can't think of any other gas limited to only hydrogen and oxygen
hope it helps :)
Yeeeeeeeeeeeeeeeeeeeeeees