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katrin [286]
1 year ago
8

In what way do the oceans and the forests perform a similar function in the carbon cycle, under normal conditions?.

Chemistry
1 answer:
ikadub [295]1 year ago
8 0

Both take carbon dioxide out of the atmosphere.

The ocean absorbs much of the carbon dioxide released when fossil fuels are burned. This extra carbon dioxide lowers the ocean's pH through a process called ocean acidification. Both are important elements for all life on earth. Relationship between the water cycle and the carbon cycle. The sun's energy drives both the carbon cycle and the water cycle.

Recall that sunlight water and carbon dioxide combine in green plants via photosynthesis to produce carbohydrates. The ocean also regulates the Earth's climate. They determine the weather by telling temperatures and determining rainfall, droughts, and floods. It is also the world's largest carbon sink, with an estimated 83% of the global carbon cycle circulating in seawater.

Learn more about The carbon cycle here:-brainly.com/question/1194643

#SPJ4

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row, period, group

Explanation:

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Which substance can be broken down by chemical means?
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Methanol is the substance that can be broken down by chemical means, the remaining ones are elements.
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Which of the following atoms would gain two electrons to fill its valence energy level?
Harlamova29_29 [7]

The atom that would gain two electrons to fill its valence energy level is S(sulfur)

This is because s (sulfur) is in atomic number 16 with 2.8.6 of [Ne] 3s^2 2p^4 electronic configuration. This implies that sulfur has 6 valence electron and therefore it require two electron to fill its valence energy level and obtain 18 rule electrons.

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The SN1 reaction yields Entry field with incorrect answer two (number) products. This is because ______________________. Entry f
vagabundo [1.1K]

Answer:

Four substitution products are obtained. The carbocation that forms can react with either nucleophile (H2O or CH3OH) from either the top or bottom side of the molecule

Explanation:

An SN1 reaction usually involves the formation of a carbocation in the slow rate determining step. This carbocation is now attacked by a nucleophile in a subsequent fast step to give the desired product.

However, the product is obtained as a racemic mixture because the nucleophile may attack from the top or bottom of the carbocation hence both attacks are equally probable.

The attacking nucleophile in this case may be water or CH3OH

4 0
3 years ago
The amount ofcalcium present in milk can be determined by adding oxalate to asample and measuring the massof calcium oxalate pre
Sauron [17]

<u>Answer:</u> The mass percent of calcium in milk is 0.107 %

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}      .....(1)

Given mass of calcium oxalate = 0.429 g

Molar mass of calcium oxalate = 128.1 g/mol

Putting values in equation 1, we get:

\text{Moles of calcium oxalate}=\frac{0.429g}{128.1g/mol}=0.0033mol

The given chemical equation follows:

Na_2C_2O_4(aq.)+Ca^{2+}(aq.)\rightarrow CaC_2O_4(s)+2Na^+(aq.)

Sodium oxalate is present in excess. So, it is considered as an excess reagent. And, calcium ion is a limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction:

1 mole of calcium oxalate is produced from 1 mole of calcium ion

So, 0.0033 moles of calcium oxalate is produced from = \frac{1}{1}\times 0.0033=0.0033mol of calcium ions

  • Now, calculating the mass of calcium ions by using equation 1, we get:

Moles of calcium ions = 0.0033 moles  

Molar mass of calcium ions = 40 g/mol

Putting values in equation 1, we get:

0.0033mol=\frac{\text{Mass of calcium ions}}{40g/mol}\\\\\text{Mass of calcium ions}=(0.0033mol\times 40g/mol)=0.132g

  • To calculate the mass percentage of calcium ions in milk, we use the equation:

\text{Mass percent of calcium ions}=\frac{\text{Mass of calcium ions}}{\text{Mass of milk}}\times 100

Mass of milk = 125 g

Mass of calcium ions = 0.132 g

Putting values in above equation, we get:

\text{Mass percent of calcium ions}=\frac{0.132g}{125g}\times 100=0.107\%

Hence, the mass percent of calcium in milk is 0.107 %

7 0
3 years ago
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