Answer:
![\large \boxed{\text{98 m$\cdot$s}^{-2}}](https://tex.z-dn.net/?f=%5Clarge%20%5Cboxed%7B%5Ctext%7B98%20m%24%5Ccdot%24s%7D%5E%7B-2%7D%7D)
Explanation:
The formula for the velocity of the ball is
![v = \sqrt{2gh}](https://tex.z-dn.net/?f=v%20%3D%20%5Csqrt%7B2gh%7D)
1. Velocity at time of impact
![v = -\sqrt{2 \times 9.807 \times 1.20} = -\sqrt{23.54} = -\textbf{4.85 m/s}](https://tex.z-dn.net/?f=v%20%3D%20-%5Csqrt%7B2%20%5Ctimes%209.807%20%5Ctimes%201.20%7D%20%3D%20-%5Csqrt%7B23.54%7D%20%3D%20-%5Ctextbf%7B4.85%20m%2Fs%7D)
2. Velocity on rebound
The ball has enough upward velocity to reach a height of 0.86 m.
![v = \sqrt{2 \times 9.807 \times 0.86} = \sqrt{16.87} =\textbf{4.11 m/s}](https://tex.z-dn.net/?f=v%20%3D%20%5Csqrt%7B2%20%5Ctimes%209.807%20%5Ctimes%200.86%7D%20%3D%20%5Csqrt%7B16.87%7D%20%3D%5Ctextbf%7B4.11%20m%2Fs%7D)
3. Acceleration
![a = \dfrac{\Delta v}{\Delta t} = \dfrac{4.11 - (-4.85)}{ 0.091} = \dfrac{8.96 }{0.091} =\textbf{98 m$\cdot$s}^{\mathbf{-2}}\\\\\text{The acceleration while the ball is in contact with the floor is $\large \boxed{\textbf{98 m$\cdot$s}^{\mathbf{-2}}}$}](https://tex.z-dn.net/?f=a%20%3D%20%5Cdfrac%7B%5CDelta%20v%7D%7B%5CDelta%20t%7D%20%3D%20%5Cdfrac%7B4.11%20-%20%28-4.85%29%7D%7B%200.091%7D%20%3D%20%5Cdfrac%7B8.96%20%7D%7B0.091%7D%20%3D%5Ctextbf%7B98%20m%24%5Ccdot%24s%7D%5E%7B%5Cmathbf%7B-2%7D%7D%5C%5C%5C%5C%5Ctext%7BThe%20acceleration%20while%20the%20ball%20is%20in%20contact%20with%20the%20floor%20is%20%24%5Clarge%20%5Cboxed%7B%5Ctextbf%7B98%20m%24%5Ccdot%24s%7D%5E%7B%5Cmathbf%7B-2%7D%7D%7D%24%7D)
Answer:
Molecular compounds consist of two or more nonmetals. The nonmetals that make up a molecular compound are held together by covalent/molecular bonds. Covalent bonds is known as the "sharing" of valence electrons between two or more chemical species. Valence electrons are shared so that the atoms of the compound can become stable, much like how ionic bonds transfer valence electrons between atoms to achieve stability.
Answer:
3.052 × 10^24 particles
Explanation:
To get the number of particles (nA) in a substance, we multiply the number of moles of the substance by Avogadro's number (6.02 × 10^23)
The mass of Li2O given in this question is as follows: 151grams.
To convert this mass value to moles, we use;
moles = mass/molar mass
Molar mass of Li2O = 6.9(2) + 16
= 13.8 + 16
= 29.8g/mol
Mole = 151/29.8g
mole = 5.07moles
number of particles (nA) of Li2O = 5.07 × 6.02 × 10^23
= 30.52 × 10^23
= 3.052 × 10^24 particles.
When air pressure is low it is Cold
Answer:
Limiting factors are resources or other factors in the environment that can lower the population growth rate. Limiting factors include a low food supply and lack of space. Limiting factors can lower birth rates, increase death rates, or lead to emigration.
Explanation: