A). 4^10 = 1,048,576 ways
b). 5^10 = 9,765,625 ways
Answer: There are 863,040 possible ways
Step-by-step explanation: There are 32 members altogether in the club. So in order to elect a president from among all of them, if every one of them has a chance if being elected, there would be 32 possible chances for every single club member.
However, as long as one member has been elected as president, that leaves others with a 31 chance per person arrangement.
Therefore, all possible permutations of electing four officers from a club of 32 members can be expressed as
32! (Thirty two factorial) which can be simplified as
32 x 31 x 30 x 29 and that equals 863,040.
863,040 possible ways of electing four officers from a club of 32 members.
It would be A) The angles are angle bisectors
I am 90% sure
This is the sum of the arithmetic sequence:
10 - 2 + 6 + 14 + ... + 110
where: a 1 = - 10, d = 8
a n = 110
a n = a 1 + ( n - 1 ) * d
110 = - 10 + ( n - 1 ) * 8
110 = - 10 + 8 n - 8
110 + 10 + 8 = 8 n
128 = 8 n
n = 128 : 8
n = 16
∑ n = n/2 * ( a 1 + a n )
∑ 16 = 16/2 * ( -10 + 110 ) = 8 * 100 = 800
Answer:
The sum is 800.
