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Ierofanga [76]
3 years ago
13

What is the total angle of This? Pls help

Mathematics
2 answers:
dmitriy555 [2]3 years ago
7 0

Answer:

180

Step-by-step explanation:

asambeis [7]3 years ago
7 0
The and is 180 hope this helps :)
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What is 70/10 equivalent fraction?
kaheart [24]
The answer is 7 because 70 ÷ 10 = 7.
6 0
3 years ago
Find a in the figure below and place the value in the empty box
AleksAgata [21]

Answer:

a = 12m

Step-by-step explanation:

In order to solve this problem we will need to know the Pythagoras theorem that states that in a right angled triangle the square of the hypotenuse (the side opposite to the right angel) is equal to  the sum of the squares of the other two sides. This theorem can be written as an equation....

c^{2} = a^{2}  + b^{2}

Now we can see that we can easily find the missing value by using this theorem. We just have to substitute the values. And we get the following

c^{2} = a^{2} + b^{2}

a^{2} = c^{2} - b^{2}

a^{2} = 15^{2} - 9^{2}

a^{2} = 225 - 81

a^{2} = 144

a = \sqrt{144}

a = 12

7 0
3 years ago
Show me a graph that best represents the solution set to the system of a linear inequalities; y-x>0. y-1>0
tangare [24]
<h2>Answer:</h2>

The graph is shown in the attached image

4 0
3 years ago
Express the function graphed on the axes below as a piecewise function.
dangina [55]

Answer:

y = 2/3x +6  for x< -3

y = 2/3x +1     for x> 3

Step-by-step explanation:

The graph is a line for  x < -3

( - 6,2) and ( -3,4)

The slope is m= ( y2-y1)/(x2-x1)

m = ( 4-2)/(-3 - -6) = 2/ ( -3+6) = 2/3

The slope is 2/3

Using point slope form

y-y1 = m(x-x1)  and the point ( -6,2)

y -2 = 2/3(x - -6)

y -2 = 2/3(x +6)

y-2 = 2/3 x +4

y = 2/3x +6 x< -3

The graph is a line for  x > 3

(3,3) and ( 6,5)

The slope is m= ( y2-y1)/(x2-x1)

m = ( 5-3)/(6-3) = 2/ (3) = 2/3

The slope is 2/3

Using point slope form

y-y1 = m(x-x1)  and the point (6,5)

y -5 = 2/3(x - 6)

y-5 = 2/3 x -4

y = 2/3x +1   x> 3

8 0
3 years ago
Consider the vector b⃗ b→b_vec with length 4.00 mm at an angle 23.5∘∘ north of east. What is the y component bybyb_y of this vec
Stells [14]

Answer:

  • \large\boxed {1.59 mm}

Explanation:

<u>1. Given vector:</u>

  • length: 4.00 mm = magnitude of the vector
  • angle: 23.5º north of east = 23.5º from the x-axys (counterclockwise)

<u>2. y-component</u>

The y-component may be determined using the sine ratio, the angle from the x-axys (counterclockwise direction), and the magnitude of the vector.

  • sine (23.5º) = y-component / magnitude

  • y-component = magnitude × sine (23.5º) = 4.00 mm × sine (23.5º) = 1.59 mm.

  • \large\boxed{y-component = 1.59 mm}

7 0
3 years ago
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