The answer to your problem is that Marisol’s shadow would be 144 feet long
we know that
arithematic sequence will always have common difference
(a)
−5, −7, −10, −14, −19, …
we can see that
![d_1=-7+5=-2](https://tex.z-dn.net/?f=%20d_1%3D-7%2B5%3D-2%20)
![d_2=-10+7=-3](https://tex.z-dn.net/?f=%20d_2%3D-10%2B7%3D-3%20)
they are not equal
so, this is not arithematic sequence
(2)
1.5, −1.5, 1.5, −1.5, …
we can see that
![d_1=-1.5-1.5=-3](https://tex.z-dn.net/?f=%20d_1%3D-1.5-1.5%3D-3%20)
![d_2=1.5+1.5=3](https://tex.z-dn.net/?f=%20d_2%3D1.5%2B1.5%3D3%20)
they are not equal
so, this is not arithematic sequence
(3)
4.1, 5.1, 6.2, 7.2, …
we can see that
![d_1=5.1-4.1=1](https://tex.z-dn.net/?f=%20d_1%3D5.1-4.1%3D1%20)
![d_2=6.2+5.1=1.1](https://tex.z-dn.net/?f=%20d_2%3D6.2%2B5.1%3D1.1%20)
they are not equal
so, this is not arithematic sequence
(4)
−1.5, −1, −0.5, 0, …
we can see that
![d_1=-1+1.5=0.5](https://tex.z-dn.net/?f=%20d_1%3D-1%2B1.5%3D0.5%20)
![d_2=-0.5+1=0.5](https://tex.z-dn.net/?f=%20d_2%3D-0.5%2B1%3D0.5%20)
they are equal
so, this is arithematic sequence
The margin of error of a given statistic is an amount that is allowed for in case of miscalculation or change of circumstances.
It is usually the radius or half of the width of the confidence interval of that statistic.
Given that a<span>
survey of the students in Lance’s school found that 58% of the
respondents want the school year lengthened, while 42% think it should
remain the same. The margin of error of the survey is ±10%.
This means that 58% </span><span>± 10% of the </span>respondents want the school year lengthened, while 42% <span><span>± 10% think it should
remain the same.</span>
Thus, from 48% to 68% </span><span><span>of the respondents want the school year lengthened, while from 32% to 52% <span>think it should
remain the same.</span> </span>
Therefore, according to
the survey data, at least 32% of students want the duration of the school
year to remain unchanged, and at least 48% want the school year to be
lengthened.</span>
Diameter = 8 cm
radius = diameter/2 = 4 cm
A = pi * r^2
A = pi * (4 cm)^2
A = 16pi cm^2