Answer:
V=πr2h
3=π·32·7
3≈65.97345
V≈65.97
Step-by-step explanation:
I don’t know the answer but I hope someone else doesnt
Answer:
<em><u>Note: I'm not sure all of this is correct</u></em> O_o
Part A
- Male IQR = Q₃ - Q₁ ≈ 15 - 5 ≈ 10
- Female IQR = Q₃ - Q₁ ≈ 9 - 2 ≈ 7
Part B
- Male Median = Q₂ ≈ 9 to 10
- Female Median = Q₂ ≈ 6 to 7
Difference ≈ 10 - 7 or 10 - 6 ≈ 3 to 4
Part C
<em>Male data distribution</em>
- <u>Shape</u>: The distribution is skewed right.
- <u>Outliers</u>: There doesn't appear to be any clear outliers on the box-plot.
- <u>Center</u>: Because the data is skewed, use median because it's a resistant measure of center. The median appears to be around 9 to 10.
- <u>Spread</u>: Because the data is skewed, use IQR because it's a resistant measure of spread. The IQR is calculated by subtracting the third quartile from the first quartile and appears to be around 10.
<em>Female data distribution</em>
- <u>Shape</u>: The distribution is slightly skewed right, but appears to have more normality than the male distribution
- <u>Outliers</u>: There appears to be one significant outliers at around 30 to 35 that is greatly larger than the rest of the data and is represented as a dot outside the box plot.
- <u>Center</u>: Because the data is skewed, use median because it's a resistant measure of center. The median appears to be around 6 to 7.
- <u>Spread</u>: Because the data is skewed, use IQR because it's a resistant measure of spread. The IQR is calculated by subtracting the third quartile from the first quartile and appears to be around 7.
Median would be a better measure of center for each because both data distributions aren't as symmetric/normal and have a skewed shape. Therefore, the median should be used because of its resistance, as it's not as impacted by extreme values as the mean.
Part D
There doesn't appear to be an outlier in the male dataset, but there appears to be a significantly large outlier in the female dataset, which might mean that there is a significantly large number of females(around 30 to 40) attending the latest superhero movie during a specific day of the study month. This might be due to a discount to the movie ticket that day for females, which attracts large number of females to watch the movie.
The answer is: "123454321"
Hope this helps!