All categories

2 years ago

In how many ways can the letters BEACH be rearranged

Mathematics

1 answer:

Nataly [62]2 years ago

8 0

I Think you can make 3

You might be interested in

6m^2 + 7n Identify the constant, variable, and terms

Leokris [45]

<h3>Answer:</h3>

Given equation :- 6m² + 7n

where,

Constant = 0.
Variable = m, n.
Terms = 6m² , 7n.

6 0

2 years ago

Find x in this 45°-45°-90° triangle. x =

Leokris [45]

Answer:

x = 1.2√2

Step-by-step explanation:

Taking the cosine value of the angle :

cos 45° = 1.2/x
1/√2 = 1.2/x
x = 1.2√2

4 0

1 year ago

Read 2 more answers

(_____)^2= (cscx-1)(cscx+1)

Lady bird [3.3K]

$(csc(x)-1)(csc(x)+1)=csc^2(x)-1=cot^2(x)$

We know that $csc^2(x)-1=cot^2(x)$ because of the Pythagorean trig identity $1+cot^2(x)=csc^2(x)$ .

4 0

3 years ago

Li walks at a constant rate of 7 ft. in 4 seconds. The table shows the relationship of feet to seconds. What is the constant of

Kisachek [45]

Answer:

The rate is 1.75 feet/seconds or 105 feet/minute.

Step-by-step explanation:

Given that,

Li walks at a constant rate of 7 feet in 4 seconds

To find the constant of proportionality, divide 7 feet by 4 seconds.

So,

$k=\dfrac{7\ \text{feet}}{4\ \text{seconds}}\\\\k=1.75\ \text{ft/s}$

1.75 ft/s is the constant of proportionality

We know that, 1 minute = 60 seconds

k = 105 feet/minute

So, the rate is 1.75 feet/seconds or 105 feet/minute.

4 0

2 years ago

From a random sample of 58 businesses, it is found that the mean time the owner spends on administrative issues each week is 21.

zzz [600]

Answer: (20.86, 22.52)

Step-by-step explanation:

Formula to find the confidence interval for population mean :-

$\overline{x}\pm z^*\dfrac{\sigma}{\sqrt{n}}$

, where $\overline{x}$ = sample mean.

z*= critical z-value

n= sample size.

$\sigma$ = Population standard deviation.

By considering the given question , we have

$\overline{x}= 21.69$

$\sigma=3.23$

n= 58

Using z-table, the critical z-value for 95% confidence = z* = 1.96

Then, 95% confidence interval for the amount of time spent on administrative issues will be :

$21.69\pm (1.96)\dfrac{3.23}{\sqrt{58}}$

$=21.69\pm (1.96)\dfrac{1.7}{7.61577}$

$=21.69\pm (1.96)(0.223221)$

$\approx21.69\pm0.83$

$=(21.69-0.83,\ 21.69+0.83)=(20.86,\ 22.52)$

Hence, the 95% confidence interval for the amount of time spent on administrative issues = (20.86, 22.52)

7 0

3 years ago