3 years ago

In how many ways can the letters BEACH be rearranged

Mathematics

1 answer:

Nataly [62]3 years ago

8 0

I Think you can make 3

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3 years ago

How many roots does the polynomial function, y=(x-8)(x+3)^2 have?

Scorpion4ik [409]

Answer:

(A) 2

Step-by-step explanation:

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Root 2: x = -3

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3 years ago

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3 years ago

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3 years ago

Use the quadratic formula to solve the<br> quadratic equation. SHOW ALL WORK.<br> 2 −8+41 = 0

horsena [70]

Answer:

Solving the equation $x^2-8x+41=0$ using quadratic formula we get $x=4+5i \ or \ x=4-5i$

Step-by-step explanation:

We need to solve the equation $x^2-8x+41=0$ using quadratic formula.

The quadratic formula is:

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

where a=1, b=-8 and c=41

Putting values in formula and finding x

$$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$\\$x=\frac{-(-8)\pm\sqrt{(-8)^2-4(1)(41)}}{2(1)}$\\$x=\frac{8\pm\sqrt{64-164}}{2}$\\$x=\frac{8\pm\sqrt{-100}}{2}$\\We \ know \ \sqrt{-1}=i\\x=\frac{8\pm10i}{2}\\x=\frac{8+10i}{2} \ or \ x=\frac{8-10i}{2}\\x=4+5i \ or \ x=4-5i$

So, Solving the equation $x^2-8x+41=0$ using quadratic formula we get $x=4+5i \ or \ x=4-5i$

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3 years ago