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Katarina [22]
2 years ago
12

Which side in the smallest triangle would correspond with HI in the largest triangle?

Mathematics
1 answer:
tensa zangetsu [6.8K]2 years ago
5 0

The side of the small triangle that will correspond to the side of HI is side IK.

<h3>How to find corresponding side of similar triangles?</h3>

Similar triangles are triangles that have the same shape but different size.

In similar triangles, corresponding sides are always in the same ratio.

The corresponding angles are equal.

Therefore, the side of the small triangle that will correspond to the side of HI is side IK.

learn more on triangle here: brainly.com/question/26531534

#SPJ1

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URGENT
mixas84 [53]

Answer:

y=7

Step-by-step explanation:

When ever the slope is 0, the line is completely flat. This means that the equation has the same y for every point.

The y on the point given is 7, therefore the answer is y=7.

8 0
3 years ago
Renee is a slaes associate at a store.She earns $80 a week plus a 15% commission on her sales . Last week,she sold $200 worth of
alex41 [277]
Renee earns a 15% commission on her $200 sales.
0.15 * 200 = $30
So, she earns 30 dollars from commission.

She also earns $80 a week, which makes a total of 80 + 30 = $110

Hence, the answer is $110
5 0
3 years ago
What is the simplified form of the following expression?
ziro4ka [17]

For this case we must simplify the following expression:7 (\sqrt [3] {2x}) - 3 (\sqrt [3] {16x}) - 3 (\sqrt [3] {8x})

We rewrite:

16x = 2 ^ 3 * 2x\\8x = 2 ^ 3 * x

We rewrite the expression:

7 (\sqrt [3] {2x}) - 3 (\sqrt [3] {2 ^ 3 * 2x}) - 3 (\sqrt [3] {2 ^ 3 * x}) =

By definition of properties of powers and roots we have:

\sqrt [n] {a ^ m} = a ^ {\frac {m} {n}}

Then, taking the terms of the radical:

7 (\sqrt [3] {2x}) - 3 (2 \sqrt [3] {2x}) - 3 (2 \sqrt [3] {x}) =\\7 \sqrt [3] {2x} -6 \sqrt [3] {2x} -6 \sqrt [3] {x} =

We add similar terms:

\sqrt [3] {2x} -6 \sqrt [3] {x}

Answer:

Option C

7 0
3 years ago
4. The distance light travels in one year is approximately 5,870,000,000,000 miles. The distance light travels in 100 years is:
jolli1 [7]
<h3><em><u>given</u></em><em><u>;</u></em></h3>

<em><u>5,870,000,000,000 miles.</u></em>

<h3><em><u>to</u></em><em><u> </u></em><em><u>find</u></em><em><u>:</u></em></h3>

<em><u>The distance light travels in 100 years</u></em><em><u>.</u></em>

<h3><em><u>solution</u></em><em><u>:</u></em></h3>

<em><u>The distance of the light travels in 100 years is:</u></em>

<em><u>5,870,000,000,000 × 100 miles.</u></em>

<em><u>= 587,000,000,000,000 miles</u></em>

<em><u>= 587 × 10</u></em><em><u>^</u></em><em><u>12 miles.</u></em>

<em><u>answer</u></em><em><u>=</u></em><em><u> </u></em><em><u>option</u></em><em><u> </u></em><em><u>d</u></em>

7 0
2 years ago
How many different 2-digit numbers are there with the following property:the tenth digit is greater than the units digit?
Serggg [28]

Answer:

45

Step-by-step explanation:

Simply start by listing out the numbers from smallest to largest.

We start out with the smallest number following this information being the number 10. The next are 21 and 20. The next are 32, 31, and 30. We can start to see a pattern. If the ten's digit is n, then there are n numbers within that ten-group that have a greater 10's digit than unit's digit. The largest ten-group (90 to 98) has 9 integers following the rules established. Thus, the number of 2-digit integers that have ten's digits greater than units digit is 1+2+3+...+9=45

7 0
2 years ago
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