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julia-pushkina [17]
2 years ago
12

Find the number of primes less than 190 using the principle of inclusion-exclusion.

Mathematics
1 answer:
Troyanec [42]2 years ago
8 0

The number of primes less than 190 using the principle of inclusion-exclusion are 42

<h3>Principle of inclusion- exclusion</h3>

The principle of inclusion-exclusion is known as a counting technique that computes the number of elements satisfying at least one of several properties and guaranteeing that the numbers are not counted twice.

Prime numbers are numbers only divisible by 1 and itself.

Prime numbers less than 190 are:

2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97, 101, 103, 107, 109, 113, 127, 131, 137, 139, 149, 151, 157, 163, 167, 173, 179, 181

They are 42 in number

Therefore, the number of primes less than 190 using the principle of inclusion-exclusion are 42

Learn more about prime numbers here:

brainly.com/question/874965

#SPJ11

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Answer:   P(A\cap B)=\frac{1}{3}

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Step-by-step explanation:

From the given figure it can be seen that

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Therefore,

P(A\cap B)=\frac{n(A\cap B)}{n(s)}=\frac{2}{6}=\frac{1}{3}

Also, The number of elements in A = 2

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P(A)=\frac{n(A)}{n(s)}=\frac{2}{6}=\frac{1}{3}

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P(B)=\frac{n(B)}{n(s)}=\frac{6}{6}=1

The formula to find the conditional probability is given by :-

P(A|B)=\frac{P(A\cap B)}{P(B)}\\\\\Rightarrow P(A|B)=\frac{\frac{1}{3}}{1}=\frac{1}{3}

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