The formula for the confidence interval is given by
Sample mean + z*[σ/√n], and
Sample mean - z*[σ/√n]
We have:
Sample mean = 23.95
n = 40
σ = 2.55
z* for 99% confidence = 2.58
Substitute these values into the formula, we have
23.95 + (2.58)(2.55÷√40) = 24.99
23.95 - (2.58)(2.55÷√40) = 22.91
So the lower interval is 22.91 and the highest interval is 24.99
Answer:
Simplifying
f(r) = 5 + 1.75r
Multiply f * r
fr = 5 + 1.75r
Solving
fr = 5 + 1.75r
Solving for variable 'f'.
Move all terms containing f to the left, all other terms to the right.
Divide each side by 'r'.
f = 5r-1 + 1.75
Simplifying
f = 5r-1 + 1.75
Reorder the terms:
f = 1.75 + 5r-1
Step-by-step explanation:
tada i think
First row, the answer on the left , -5 3/4 - 4 2/3
Answer:
2.8 feet
Step-by-step explanation:
tan(29)=x/5
5tan(29)=x
2.8=x
Answer:
Average employee [Mean] = 43.6
Step-by-step explanation:
Given:
Interval Number of employee
25-35 20
35-45 7
45-55 8
55-65 15
Total 50
Find:
Average employee [Mean]
Computation:
Interval X[u+l]/2 Number of employee fx
25-35 30 20 600
35-45 40 7 280
45-55 50 8 400
55-65 60 15 900
Total 50 2,180
Average employee [Mean] = Sum of fx / Sum of x
Average employee [Mean] = 2,180 / 50
Average employee [Mean] = 43.6
