A shuttle stays in orbit because of the gravitational pull of earth its just like how the moon is able to orbit the earth
Answer:
(a). The power delivered to the element is 187.68 mW
(b). The energy delivered to the element is 57.52 mJ.
Explanation:
Given that,
Charge
Voltage
Time t = 0.3 sec
We need to calculate the current
Using formula of current
Put the value of charge
(a).We need to calculate the power delivered to the element
Using formula of power
Put the value into the formula
Put the value of t
(b). We need to calculate the energy delivered to the element between 0 and 0.6 s
Using formula of energy
Put the value into the formula
Hence, (a). The power delivered to the element is 187.68 mW
(b). The energy delivered to the element is 57.52 mJ.
I didn't have a dollar bill handy. So I conducted an extensive, exhaustive, in-depth, 2-minute internet search to determine the length of one. (I lived in Boston for 6 years and it had a profound effect on me. All during the 2 minutes of my research, I kept mumbling "dorla bill" to myself.) Anyway, the length of a US dorla bill is 6.14 inches.
We want to find out HOW MANY dorla bills it would take. We don't know that number yet, but we need to use it in our math, so we have to use something to put in its place until we find out the actual number. Most people would use 'x'. I'm going to use ' M '.
Length of 1 bill . . . . . 6.14 inches
Length of ' M ' bills . . . . . (6.14 M) inches
Circumference of the Earth at the equator . . . . . 40,075 km
inches in 1 foot . . . . . 12
feet in 1 meter . . . . . 3.28084
meters in 1 km . . . . . 1,000
This is all the outside information we need. The rest is all arithmetic.
==========================================
length of 1 bill, in inches . . . . . 6.14 inches
length of ' M ' bills, in inches . . . . . (6.14 M inches)
length of ' M ' bills, in feet . . . . .(6.14 M inches) x (1 foot/12 inches)
length of ' M ' bills, in meters . . . . .
(6.14 M inches) x (1 foot/12 inches) x (1 meter/3.28084 foots)
length of ' M ' bills, in km . . . . . (6.14 M inches) x(1 foot/12 inches) x(1 meter/3.28084 foots) x(1 km/1,000 m)
. . . . . . . . . . ^ these numbers are equal \/ . . . . . . . . . .
Circumference of the equator . . . . . 40,075 km
==============================================
Gather all the numbers together, and all the units together:
(6.14M x 1 x 1 x 1)/(12 x 3.28084 x 1,000) x (inch-foot-meter-km/inch-foot-meter) = 40,075 km
Do the arithmetic, and cancel out units that appear on both top and bottom:
(0.000155956 M) x (km) = 40,075 km
Divide each side by 0.000155956 km, and you'll have:
M = (40,075 / 0.000155956)
M = 256.96 million bills
============================================
Quick check, just to see if it makes sense:
Round each dorla bill to 6 inches even:
(256.96 million x 6 inches) x (1 ft/12 inch) x (1 mile/5280 ft) = 24,333 miles
Well, the same internet says the equator's circumference is 24,901 miles. YAY ! ! ! As an engineer, I'd say the two numbers match perfectly. So the answer to the question is confirmed to be
256.96 million bills
(2.57 x 10⁸ bills)
Hello!
Pseudoscience in a sentence is "A pseudoscience is set of ideas based on theories put forth as scientific when they are not scientific."