Answer:
Sorry for being late. It is...
A.) X: Load, Y: Fulcrum, Z: Lever
Fk = μK N
N = m a
N = 4 × a
N = 4a
Fk = μK N
17 = 5 × 4a
17 = 20 a
a = ¹⁷/₂₀ = 0.85 m/s²
Explanation:
In first case, the forces on LHS and on RHS is the same i.e. 3 N. The force acting on the car is balanced force. As a result, the car will not move at all.
In second case,
Force on RHS = 2000 N
Force on LHS = -6000 N
Net force acting on it is given by :
F = 2000+(-6000)
= -4000 N
Hence, this is the required solution.
Answer:
0.79
Explanation:
Using Snell's law, we have that:
n(1) * sin θ1 = n(2) * sinθ2
Where n(1) = refractive index of air = 1.0003
θ1 = angle of incidence
n(2) = refractive index of second substance
θ2 = angle of refraction
The angle of reflection through the unknown substance is the same as the angle of incidence of air. This means that θ1 = 32°
=> 1.0003 * sin32 = n(2) * sin42
n(2) = (1.0003 * sin32) / sin42
n(2) = 0.79
