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stepladder [879]

3 years ago

5

A car has a mass of 1 200 kg. A very strong weightlifter attempts, unsuccessfully, to lift the car by applying an upward force o

f 2 500 N. What is the normal force acting on the car as the weightlifter is applying this force? Be sure to include a force diagram in your answer.

1 answer:

Setler79 [48]3 years ago

4 0

Answer:check the pic

Explanation:

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The position of an electron is given by , with t in seconds and in meters. At t = 3.99 s, what are (a) the x-component, (b) the

egoroff_w [7]

Answer:

A. Vx = 3.63 m/s

B. Vy = -45.73 m/s

C. |V| = 45.87 m/s

D. θ = -85.46°

Explanation:

Given that position, r, is given as:

r = 3.63tˆi − 5.73t^2ˆj + 8.16ˆk

Velocity is the derivative of position, r:

V = dr/dt = 3.63 - 11.46t^j

A. x component of velocity, Vx = 3.63 m/s

B. y component of velocity, Vy = -11.46t

t = 3.99 secs,

Vy = - 11.46 * 3.99 = -45.73 m/s

C. Magnitude of velocity, |V| = √[(-45.73)² + 3.63²]

|V| = √(2091.2329 + 13.1769)

|V| = √(2104.4098)

|V| = 45.87 m/s

D. Angle of the velocity relative to the x axis, θ is given as:

tanθ = Vy/Vx

tanθ = -45.73/3.63

tanθ = -12.6

θ = -85.46°

7 0

4 years ago

Honeybees acquire a charge while flying due to friction with the air. A 100 mg bee with a charge of +23 pC experiences an electr

Sedbober [7]

Answer:

(A) ratio of electric force to weight will be $23.469\times 10^{-10}$

(b) Electric field will be $E=4.26\times 10^{10}N/C$

Explanation:

We have given mass of bee = 100 mg = $m=100\times 10^{-3}=0.1kg$

Charge on bee $q=23pC=23\times 10^{-12}C$

Electric field E = 100 N/C

Weight of the bee $W=mg=0.1\times 9.8=0.98N$

Electric force on the bee $F=qE=23\times 10^{-12}\times 100=23\times 10^{-10}N$

So the ratio of electric force on the bee and weight is $=\frac{F}{W}=\frac{23\times 10^{-10}}{0.98}=23.469\times 10^{-10}$

(B) To hold the bee in air electric force must be equal to weight of bee

So $mg=qE$

$0.1\times 9.8=23\times 10^{-12}E$

$E=4.26\times 10^{10}N/C$

4 0

3 years ago

A 0.1 kg tennis ball is brought from a speed of 15m/s to a speed of 45 m/s when hit by a tennis racket. If this done over 0.05 s

Hitman42 [59]

45 lolololololololol

5 0

3 years ago

A proton and an electron are released from rest in the center of a capacitor.

Sunny_sXe [5.5K]

Answer:

a) equal 1, b) less than 1

Explanation:

a) the electric force is given by

Fe = q E

The charge of the electron and proton has the same value, that of the proton is positive and that of the electron is negative

Proton

Fp = qE

Electron

Fe = - q E

Fp / Fe = -1

If we do not take into account the sign the relationship is equal to one (1)

b) to calculate the force we use Newton's second law

F = ma

qE = m a

a = q E / m

The mass of the proton much greater than the mass of the electron

ap = q E / $m_{p}$

ae = - q E / $m_{e}$

ap / ae = $m_{e}$ / $m_{p}$ = $m_{e}$ /1600 $m_{e}$ =1/1600

It is much smaller than 1

7 0

3 years ago

Sam blew up a balloon and rubbed it on his head. Then he stuck the balloon on the wall. This was all the result of electrostatic

Reika [66]

Answer:

If the balloon acquires charge, Sam's hair loses charge.

Explanation:

I JUST TOOK THE IA4 AND GOT THIS ONE RIGHT. IF ANY OF YA'LL ARE LOOKING FOR A SIGN, HERE IT IS, YOU W I L L PASS THIS TEST

4 0

3 years ago