From the calculation, we can see that the force that moves the box forward is 5.7 N.
<h3>What is frictional force?</h3>
The term frictional force refers to the force that opposes motion. Given that;
ma = ukmgcosθ + F
Let F be the forward force.
Hence;
F = ma - ukmgcosθ
F = 4 * 3 - (0.32 * 4.00 * 9.8 * sin 30)
F = 5.7 N
Learn more about frictional force:brainly.com/question/14662717
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Answer:

Explanation:
The volume charge density is defined by ρ =
(Equation A), where Q is the charge and V, the volume.
The units in the S.I. are
, so we have to express the radius in meters:
inner radius = 
outer radius = 
Now, we know that the volume of the sphere is calculated by the formula:
, and as we have an spherical shell, the volume is calculated by the difference between the outher and inner spheres:
V =
, where
is the outer radius and
is the inner radius.
Replacing the volume formula in the Equation A:
ρ = 
ρ = 
Replacing the values of the outer and inner radius whe have:
ρ = 
ρ = 
The two additional forces that act on the ball as it travels between the pitcher and the home plate are air resistance and gravity.
<h3>What are the forces that affect object in motion;</h3>
- Air resistance: this is the force that oppose the motion of an object in air due to frictional force
- Gravity: this is the force due to weight of the object and acts downwards.
The two additional forces that act on the ball as it travels between the pitcher and the home plate include:
- Air resistance and
- Gravitational force
<h3>How the forces affect the motion of the ball</h3>
- Air resistance oppose the motion of the ball as it travels in air.
- Gravity is the force due to weight of the ball and acts downwards.
Learn more about forces on object in motion here: brainly.com/question/10454047
Explanation:
The force is 186.5 N. 3.8% of the force is directed downward. So the vertical component of the force is:
Fᵧ = 0.038 (186.5 N)
Fᵧ = 7.087 N
The horizontal component is found with Pythagorean theorem:
F² = Fₓ² + Fᵧ²
(186.5 N)² = Fₓ² + (7.087 N)²
Fₓ = 186.4 N
So the work done is:
W = Fd
W = (186.4 N) (7.4 m)
W = 1379 J
Round as needed.