Gibbons, small Asian apes, move by brachiation, swinging below a handhold to move forward to the next handhold. A 9.0 kg gibbon
1 answer:
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(a) The magnitude of the electric field at point 5.5m is 2.35 x 10⁴ N/C.
(b) The magnitude of the electric field at point 2.5m is 5.18 x 10⁴ N/C.
<h3>Electric field at a point on the Gaussian surface</h3>
The magnitude of the electric field at a point on the cylindrical Gaussian surface is calculated as follows;
E = λ/2πε₀r
where;
- λ is linear charge density
- ε₀ is permitivity of free space
- r is the position of the charge
Thus, the magnitude of the electric field at points of 5.5m is 2.35 x 10⁴ N/C, and the magnitude of the electric field at points of 2.5m is 5.18 x 10⁴ N/C.
Learn more about electric field here: brainly.com/question/14372859
Answer:
The vehicle displacement is 9.90 feet.
Explanation:
Given that,
Height of tree = 4.5 feet
Distance = 33 feet
According to figure,
We need to calculate the value of l
Using Pythagorean theorem
We need to calculate the vehicle displacement
Using horizontal component
Vehicle displacement =horizontal component of pulled rope
Where, is angle between rope and ground
d = pulled length of rope
Hence, The vehicle displacement is 9.90 feet.
