Equation 1: -6x = 26 - 20y
Equation 2: -8x = 8-20y
Step 1: Cancel out the Ys
-6x = 26 - 20y --> -6x = 26 - 20y
(-8x = 8-20y) x -1 --> + 8x = -8 + 20y
------------------------
2x = 18
x = 9
Step 2: Plug in X and solve for Y (P.S. you can plus X into either of the equations)
-6(9) = 26 -20y
-54 = 56 - 20y
-80 = -20y
y = 4
Step 3: Check the answer:
-6(9) = 26 - 20(4)
-54 = -54
Therefore:
x = 9 y = 4
Set it up as a proportion
115/5=n/15
And then you cross multiply
5•n=15•115
5n=1725
n=345 miles
7 squared = 49 and 9 squared= 81 add up 49 and 81 and you get 130
Answer:
Counselor's estimate isn't correct.
Step-by-step explanation:
Total number of students in university = 30,600
2% break 3 of the languages
Therefore, 2/100 × 30600 = 612 students break 3 of the languages in the University according to the counselor.
In a random sample of 240 students, 20 break 3 of the languages.
% = 20/240 × 100 = 8.33%
SinceTotal number of students = 30,600
Therefore, 30,600/240 = 127.5
Which means 127.5 × 20 = 2550.
Which means 2550 students break 3 of the languages as against the 612 students stated by the counselor.
