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1 year ago

WILL GIVE BRAINLIEST

Chemistry

1 answer:

seropon [69]1 year ago

3 0

Answer:

Chemical reaction A, because the reactant is a compound

Explanation:

In a decomposition reaction, a compound is broken down into its components, so the number of products is greater than the number of reactants

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Using complete subshell notation (not abbreviations, 1s 22s 22p 6 , and so forth), predict the electron configuration of each of

dybincka [34]

Answer: The electronic configuration of the elements are written below.

Explanation:

Electronic configuration is defined as the representation of electrons around the nucleus of an atom.

Number of electrons in an atom is determined by the atomic number of that atom.

For the given options:

Option a: Carbon (C)

Carbon is the 6th element of the periodic table. The number of electrons in carbon atom are 6.

The electronic configuration of carbon is $1s^22s^22p^2$

Option b: Phosphorus (P)

Phosphorus is the 15th element of the periodic table. The number of electrons in phosphorus atom are 15.

The electronic configuration of phosphorus is $1s^22s^22p^63s^23p^3$

Option c: Vanadium (V)

Vanadium is the 23rd element of the periodic table. The number of electrons in vanadium atom are 23.

The electronic configuration of vanadium is $1s^22s^22p^63s^23p^64s^23d^3$

Option d: Antimony (Sb)

Antimony is the 51st element of the periodic table. The number of electrons in antimony atom are 51.

The electronic configuration of antimony is $1s^22s^22p^63s^23p^64s^23d^{10}4p^65s^24d^{10}5p^3$

Option e: Samarium (Sm)

Samarium is the 62nd element of the periodic table. The number of electrons in samarium atom are 62.

The electronic configuration of samarium is $1s^22s^22p^63s^23p^64s^23d^{10}4p^65s^24d^{10}5p^66s^24f^6$

Hence, the electronic configuration of the elements are written above.

4 0

2 years ago

Single strand RNA is made using the genetic instructions from double strand DNA.

ale4655 [162]

False I’m pretty sure

3 0

2 years ago

The rate constant for a first-order reaction is 0.54 s-1. What is the half-life of this reaction if the initial concentration is

Diano4ka-milaya [45]

Answer:

The half life time of first order reaction is 1.3 sec

Explanation:

Given:

First order rate constant $K = 0.54$ $M^{-1} s^{-1}$

Initial concentration $= 0.54$ M

From the formula of first order half life time,

$K = \frac{0.693}{t_{\frac{1}{2} } }$

So half life time is given by,

${t_{\frac{1}{y2} } } = \frac{0.693}{0.54}$

${t_{\frac{1}{y2} } } = 1.3$ sec

Therefore, the half life time of first order reaction is 1.3 sec.

4 0

2 years ago

Which element has properties of both metals and nonmetals?

PilotLPTM [1.2K]

Metalloids have the properties of metals and nonmetals.

8 0

2 years ago

For the overall reaction below, which of the following is the correctly written rate law? Overall reaction: O3(g)+2NO2(g)→N2O5(g

zavuch27 [327]

Answer: $Rate=k[O_3][NO_2]^2$

Explanation:

Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.

$O_3(g)+NO_2(g)\rightarrow NO_3(g)+O_2(g)$ slow

$NO_3(g)+NO_2(g)\rightarrow N_2O_5(g)$ fast

To determine the net chemical equation, we will simply add the above two equations, we get:

$O_3(g)+2NO_2(g)\rightarrow N_2O_5(g)+O_2(g)$

$Rate=k[O_3][NO_2]^2$

Order with respect to $O_3$ is 1 and Order with respect to $NO_2$ is 2.

Thus the rate law will be: $Rate=k[O_3][NO_2]^2$

6 0

3 years ago