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3 years ago

Which of the following is not a reason to use an alloy instead of a pure metal?

Chemistry

2 answers:

Nikolay [14]3 years ago

7 0

Answer:

c) Cast iron is more brittle than pure iron.

Explanation:

Xelga [282]3 years ago

4 0

Cast iron is more brittle than pure iron

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BRAINLIESTT ASAP! PLEASE HELP ME :)

ruslelena [56]

Answer:

See below

Step-by-step explanation:

Matter is either a pure substance or a mixture.

Pure substances

Are composed of one type of atom or molecule.
Have a constant chemical composition
Have fixed chemical properties
Have fixed physical properties

• For example, melting point, boiling point, density, solubility

Mixtures:

Consist of two or more substances not chemically combined
Have a variable composition
Can be separated into two or more components by physical means

• For example, filtration, distillation, centrifugation

Each component retains its own properties

7 0

3 years ago

An airplane starts at rest and Excelerator down the runway for 20 seconds. At the end of the runway, its velocity is 80 m/s Nort

masha68 [24]

According to the formula you have given us to work with . . .

1). The airplane's acceleration is

(80 m/s north - zero) / (20 sec) = 4 m/sec^2 north

2). For the cyclist:

(V-final - zero) / 20sec = 0.5 m/s^2 south

Multiply each side by 20s : V-final = 0.5 m/s^2 south x (20sec) =

10 m/s south

8 0

2 years ago

Is gasoline evaporated a chemical change

Len [333]

No. The only thing that changed was the looks of the gasoline, not the chemical components.

5 0

3 years ago

Read 2 more answers

Can someone help me please ;) Will be marking someone brainliest ! Thank you

mote1985 [20]

Answer: C

Explanation:

4 0

3 years ago

lord [1]

Answer:

$\boxed{6.08 \times 10^{23}}$

Explanation:

Data:

I = 2.15 A

t = 8 min 24 s

T = 26.0 °C

V = 65.4 mL

p = 774.2 To

1. Write the equation for the half-reaction

2H₂O ⟶ O₂ + 4H⁺ + 4e⁻

2. Calculate the moles of oxygen

$p = \text{774.2 To} \times \dfrac{\text{1 atm}}{\text{760 To}} = \text{1.0187 atm}$

V = 0.0654 L

T = (26.0 + 273.15) K = 299.15 K

$\begin{array}{rcl}pV& = & nRT\\1.0189 \times 0.0654 & = & n \times 0.08206 \times 299.15\\0.06662 & = & 24.55n\\\\n & = & \dfrac{0.06662}{24.55}\\\\n & = & 2.714 \times 10^{-3}\\\end{array}$

3. Calculate the moles of electrons

$\text{n} = \text{2.714 $\times 10^{-3}$ mol oxygen} \times \dfrac{\text{4 mol electrons}}{\text{ 1 mol ozygen}} = \text{ 0.01086 mol electrons}$

4. Calculate the number of coulombs

t = 8 min 24 s =504 s

Q = It = 504 s × 2.10 C·s⁻¹= 1058 C

5. Calculate the number of electrons

$\text{No. of electrons} = \text{1058 C} \times \dfrac{\text{1 electron}}{1.602 \times 10^{-19}\text{ C}} = 6.607 \times 10^{21}\text{ electrons}$

6. Calculate Avogadro's number

$N_{\text{A}} = \dfrac{6.607 \times 10^{21}}{0.01086} = \mathbf{6.08 \times 10^{23}}\\\\\text{The experimental value of Avogadro's number is } \boxed{\mathbf{6.08 \times 10^{23}}}$

3 0

3 years ago