The answer is c hopefully I helped you
The order would be coefficient, law of conservation of mass, products, and reactants respectively.
<h3>Word matching</h3>
The number written in front of a chemical symbol in an equation is called a coefficient.
The total mass of a system being unchanged is known as the law of conservation of mass
The substances made in chemical reactions are called products.
The starting materials in chemical reactions are called reactants.
More on reactions can be found here: brainly.com/question/17434463
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The temperature is constant which makes it the independent variable
There can be two cases
Case 1:
When a molecule has one carbon-carbon double bond and four monovalent atoms or groups in which two atoms on same carbon are different, there will be 2 isomers, one cis and one trans.
Case 2:
When a molecule has one carbon-carbon double bond and four monovalent atoms or groups where both atoms attached to the same carbon are same, there will be no geometrical isomerism.
As based on priority, there will be only two orientations possible , in which same priority atoms are on the same side that is cis and if they are on the opposite side that is trans.
Answer:
760 uM
Explanation:
<em>A biochemist carefully measures the molarity of magnesium ion in 47, mL of cell growth medium to be 97 uM. Unfortunately, a careless graduate student forgets to cover the container of growth medium and a substantial amount of the solvent evaporates. The volume of the cell growth medium falls to 6.0 mL. Calculate the new molarity of magnesium ion in the cell growth medium Be sure your answer has the correct number of significant digits.</em>
The problem here is that the amount of magnesium ion remains the same irrespective of the volume.
Amount of magnesium in the growth medium = <em>molarity x volume</em>
= 97 x 
x 47 x 
= 4.559 x
Then, the volume reduced to 6.0 mL, the new molarity becomes;
<em>molarity = mole/volume </em>
= 4.559 x /6 x = 7.598333 x 
M = 759.83333 uM
To the correct number of significant digits = 760 uM
