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aleksandr82 [10.1K]
1 year ago
6

CAN YALL PLEASE WORK IT OUTTT $18.79 + $2.11 + ‐$1.92 + $17.28

Mathematics
1 answer:
Dmitry [639]1 year ago
7 0

Answer:

40.1

Step-by-step explanation:

Because the order of operations (Bodmas or Pedmas) tells you to add from left to right. So you would do 18.79 + 2.11 = 20.9, then you would do 20.90 + 1.92 (Add 0 at the end of 20.9) = 22.81. Then you will add 22.81 + 17.28 = 40.1. So your answer is 40.1. Hope this helps!

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Which volume could belong to a cube with a side length that is an integer? Recall the formula Cube volume = s cubed. 18 cubic in
irina1246 [14]

We have been given 4 choices. We are asked to choose the volume that could belong to a cube with a side length that is an integer.

We know that volume of a cube is cube of each side length.

To solve our given problem, we will take cube root of each given value. The cube root of which value will be an integer that will be our correct choice.

A. s^3=18

\sqrt[3]{s^3}=\sqrt[3]{18}

s=2.62074

Since cube root of 18 is not an integer, therefore, 18 is not a correct choice.

B. s^3=36

\sqrt[3]{s^3}=\sqrt[3]{36}

s=3.301927

Since cube root of 36 is not an integer, therefore, 36 is not a correct choice.

C. s^3=64

\sqrt[3]{s^3}=\sqrt[3]{64}

s=4

Since cube root of 64 is 4 and 4 is an integer, therefore, 64 is the correct choice.

D. s^3=100

\sqrt[3]{s^3}=\sqrt[3]{100}

s=4.641588

Since cube root of 100 is not an integer, therefore, 100 is not a correct choice.

5 0
3 years ago
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How many 1/16 inches are in one inch?
Dafna11 [192]
The answer is 16 inches are in 1/16 inches
8 0
2 years ago
First convert these fractions to twelfths then order them.Write your
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What is the solution to the system of equations?<br><br> y = 2x – 3.5<br><br> x – 2y = –14
iogann1982 [59]

Answer:

7

Step-by-step explanation:

Substitution then simplify

8 0
3 years ago
Question 1<br> What is the solution of n² - 49 = 0?<br> 0 +7<br> 07<br> -7<br> O no solution
Sphinxa [80]
Hey there!

This can be written as n^{2}-(7)^{2}

This is in form of \fbox{a^{2}-b^{2}} , it can be expanded as \fbox{(a-b)(a+b)}

=> (n-7)(n+7)=0
=> n -7 = 0 or n + 7 = 0
=> n = 7 or n = -7

So option 7 , -7 are correct.

Hope this is clear :)
Have a good day:)
7 0
2 years ago
Read 2 more answers
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