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2 years ago

Briefly describe how the micrometre screw gauge is used

Physics

1 answer:

Brums [2.3K]2 years ago

4 0

Answer:

the micrometre screw gauge is used for making precise linear measurements (e.g to measure diameter of a wire)

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Which sentence states Newton's second law?

Shalnov [3]

Answer:

Force is equal to the change in momentum per change in time.

Explanation:

That situation is described by Newton's Second Law of Motion. According to NASA, this law states, "Force is equal to the change in momentum per change in time. For a constant mass, force equals mass times acceleration." This is written in mathematical form as Force = mass.

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2 years ago

Write any three differences between metals and nonmetals

Alisiya [41]

Metals Non-metals

They are solid at room temperature. They may be solid, liquid and gas at room temperature.

They have high melting and boiling points. They have low melting and boiling points.

They are good conductors of heat and electricity. They are bad conductors of heat and electricity.

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3 years ago

Identifying Applications of Electromagnetic Waves

Anuta_ua [19.1K]

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gamma ray-destruction of cancer cells

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3 years ago

A skier moving at 5.30 m/s encounters a long, rough horizontal patch of snow having coefficient of kinetic friction 0.220 with h

larisa [96]

Answer:

6.5 m

Explanation:

First of all, we need to compute the acceleration of the skier. We know that there is only force acting on the skier: the force of friction, which is in the opposite direction to the motion of the skier. Using 2nd Newton Law:

$\sum F = ma\\F_f = ma\\-\mu m g = ma$

where $F_f = -\mu mg$ is the force of friction, with

$\mu=0.220$ is the coefficient of kinetic friction

m is the mass of the skier

$g=9.8 m/s^2$ is the acceleration due to gravity

Re-arranging the equation, we find:

$a=\mu g=-(0.220)(9.8 m/s^2)=-2.16 m/s^2$

So now we can use the following SUVAT equation to calcualte the total displacement of the skier before stopping:

$v^2 - u^2 = 2ad$

where

v = 0 is the final velocity

u = 5.30 m/s is the initial velocity

a = -2.16 m/s^2 is the acceleration

d = ? is the displacement

Solving the formula for d, we find:

$d=\frac{v^2-u^2}{2a}=\frac{0-(5.30 m/s)^2}{2(-2.16 m/s^2)}=6.5 m$

6 0

3 years ago

What is the frequency of the fundamental mode of vibration of a steel piano wire stretched to a tension of 440 n? the wire is 0.

likoan [24]

The fundamental frequency of vibration of a string is given by
$f= \frac{1}{2L} \sqrt{ \frac{T}{\mu} }$
where
L is the length of the string
T is the tension
$\mu= \frac{m}{L}$ is the linear mass density, where m is the mass of the string

Let's start by calculating the mass density of the piano wire in the problem. Its mass is
$m=5.60 g=5.60 \cdot 10^{-3} kg$
and its length is L=0.600 m, so its mass density is
$\mu= \frac{5.60 \cdot 10^{-3} kg}{0.600 m}=9.33 \cdot 10^{-3} kg/m$

Therefore now we have everything to calculate the fundamental frequency of the piano wire. Using T=440 N and the first equation, we find:
$f= \frac{1}{2 \cdot 0.600 m} \sqrt{ \frac{440 N}{9.33 \cdot 10^{-3} kg/m} } =180.9 Hz$

6 0

3 years ago

Briefly describe how the micrometre screw gauge is used​

Briefly describe how the micrometre screw gauge is used