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mel-nik [20]
2 years ago
12

Which of the following would produce the most power?

Physics
1 answer:
Fantom [35]2 years ago
6 0

Answer:

A mass of 10 kilograms lifted 10 meters in 5 seconds.

Explanation:

Power can be defined as the energy required to do work per unit time.

Mathematically, it is given by the formula;

Power = \frac {Energy}{time}

But Energy = mgh

Substituting into the equation, we have

Power = \frac {mgh}{time}

Given the following data;

Mass = 10kg

Height = 10m

Time = 5 seconds

We know that acceleration due to gravity is equal to 9.8 m/s²

Power = \frac {10*9.8*10}{5} = 490 Watts

Hence, a mass of 10 kilograms lifted 10 meters in 5 seconds would produce the most power.

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The object represented by this graph is moving
Vinil7 [7]

The object represented by this graph is moving toward the origin at constant velocity.

Option 3.

<u>Explanation:</u>

In the figure, x-axis is representing increase in the time and y-axis is presenting increase in the distance from bottom to up. But the line in the graph which is plotted is decreasing from high distance to small distance with increase in time. So this indicates that as the time is increasing, the distance is decreasing.

And the object is moving toward the origin as the distance of the object motion is found to decrease with increase of time as per the graph. But the slope of the graph is found to be almost constant, this indicates that the velocity of the object is constant. Thus, the object represented by this graph is moving toward the origin at constant velocity.

4 0
3 years ago
Read 2 more answers
The gravitational force experienced by Earth due to the Moon is ________ the gravitational force experienced by the Moon due to
Vsevolod [243]

The gravitational force experienced by Earth due to the Moon is <u>equal to </u>the gravitational force experienced by the Moon due to Earth.

<u>Explanation</u>:

The force that attracts any two objects/bodies with mass towards each other is defined as gravitational force. Generally the gravitational force is attractive, as it always pulls the masses together and never pushes them apart.

The gravitational force can be calculated effectively using the following formula: F=GMmr^2  

where “G” is the gravitational constant.

Though gravity has the ability to pull the masses together, it is the weakest force in the nature.

The mass of the Earth and moon varies, but still the gravitational force felt by the Earth and Moon are alike.

5 0
3 years ago
It takes 700 joules to lift an object straight up, but 1400 joules to push it up a ramp, what is the
crimeas [40]

Answer:

561

Explanation: it would most definitely go down as a number because it isn't the same

3 0
2 years ago
A man is pulling on a rope with a force of 63 N directed at an angle of 61◦ to the horizontal. What is the y-component of this f
Sergio039 [100]
Y = 63sin61

y = 55.1 N
6 0
3 years ago
An investigator places a sample 1.0 cm from a wire carrying a large current; the strength of the magnetic field has a particular
Sonja [21]

Answer: <em>she will have to increase the factor of current by</em> 11

Explanation: The mathematical relationship between the strength of the magnetic field (B) created by a current carrying conductor with current (I) is given by the Bio-Savart law given below

B=\frac{u_{0}I }{2\pi r}

B=strength of magnetic field

I = current on conductor

r = distance on any point of the conductor from it center

u_{0} = permeability of magnetic field in space

from the question, the investigator is trying to keep a constant magnetic field meaning B has a fixed value such as the constants in the formulae, the only variables here are current (I) and distance (r). We can get this a mathematical function.

by cross multipying, we have

B* 2πr=u_{0}<em>I </em>

by dividing through to make <em>I </em>subject of formulae, we have that

<em>I </em>= \frac{B*2\pi r}{u_{0} }

B, 2π and u_{0} are all constants, thus

\frac{B*2\pi r}{u_{0} } = k(constant)

thus we have that

<em>I </em>=kr<em> (current is proportional to distance assuming magnetic field strength and other parameters are constant) </em>

thus we have that

\frac{I_{1} }{r_{1} }=\frac{I_{2} }{r_{2} }

r_{1}=1cm and r_{2}=11cm

\frac{1_{1} }{1}=\frac{I_{2} }{11}

thus I_{2}=11* I_{1}

which means the second current is 11 times the first current

8 0
3 years ago
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