Answer:
Speed =0.283m/ s
Direction = 47.86°
Explanation:
Since it is a two dimensional momentum question with pucks having the same mass, we derive the momentum in xy plane
MU1 =MU2cos38 + MV2cos y ...x plane
0 = MU2sin38 - MV2sin y .....y plane
Where M= mass of puck, U1 = initial velocity of puck 1=0.46, U2 = final velocity of puck 1 =0.34, V2 = final velocity of puck 2, y= angular direction of puck2
Substitute into equation above
.46 = .34cos38 + V2cos y ...equ1
.34sin38 = V2sin y...equ2
.19=V2cos Y...x
.21=V2sin Y ...y
From x
V2 =0.19/cost
Sub V2 into y
0.21 = 0.19(Sin y/cos y)
1.1052 = tan y
y = 47.86°
Sub Y in to x plane equ
.19 = V2 cos 47.86°
V2=0.283m/s
The LAST choice is the correct one.
The frequency of the wave is 0.5Hertz
<h3>How to calculate the
frequency of a wave</h3>
The formula for calculating the velocity of a wave is expressed as:
velocity = frequency * wavelength
Determine the formula for the frequency
frequency = velocity/wavelength
Given the following parameters
Velocity = 1.00 m/s
wavelength = 2.00m
Determine the frequency
f = 1.00/2.00
f = 0.5Hz
Hence the frequency of the wave is 0.5Hertz
Learn more on velocity of wave here: brainly.com/question/3148541
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Answer:
Acceleration of the meteorite, 
Explanation:
It is given that,
A Meteorite after striking struck a car, v = 0
Initial speed of the Meteorite, u = 130 m/s
Distance covered by Meteorite, s = 22 cm = 0.22 m
We need to find the magnitude of its deceleration. It can be calculated using the third equation of motion as :
So, the deceleration of the Meteorite is 
. Hence, this is the required solution.
