We need to find the solution to:
(85 + 83 + 98 + 77 + x) / 5 >= 84 where x is the score in the last test
This is the same as:
(343 + x) / 5 >= 84
Multiplying both sides by 5 we get
343 + x >= 420
Subtracting 343 from both sides we get
x >= 77
There for the student must get a score of at least 77 on the last tests.
Some are
y-2=-3x
y+3x=2
3x=2-y
Cables are forming 3 right angled triangles the pole being the shared height of them;
(height) b= 12yd
(base) a= 9yd
(hypotenuse) c= ?
Need to find the long side (hypotenuse);
a^2 + b^2 = c^2
12^2 + 9^2 = 225
Take square root of 225 = 15
Then you have;
1x 12yd = 12
3x 9 yd = 27
3x 15yd = 45
Add them up = 84yd of cable needed
Answer:
100
Step-by-step explanation:
This is formula fot completing the square:
(b/2)^(2)
(-20/2)^(2)
100
Ok, this definition of f is just a bunch of points (4 to be exact).
so if point (a,b) is part of f, then f(a)=b
f(1) is about point (1,0), so f(1)=0.
g(1) = 1 (due to point (1,1))
g(2/3) = 0
f(2) = 3/4
g(-2) = 3
f(π) = -2
just a lookup once you see what is happening