The first thing we should know in this case is that by definition the flow of liquid is given by:
Q = V / t
Where,
V: volume
t: time
The volume of the cone is given by:
V = (pi * r ^ 2 * h) / (3)
Where,
r: radio
h: height
Substituting the values we have:
V = (3.14 * ((3) ^ 2) * 7) / (3)
V = 65.94 in ^ 3
We now turn off the time of the flow equation:
t = V / Q
Substituting values:
t = (65.94) / (14)
t = 4.71 minutes
Answer:
It will take for all the liquid in the funnel to pass through the nozzle about:
t = 4.71 minutes
Answer:
23.44%
Step-by-step explanation:
The probability of getting a 4 on the first 2 throws and different numbers on the last 5 throws = 1/6 * 1/6 * (5/6)^5
= 0.01116
There are 7C2 ways of the 2 4's being in different positions
= 7*6 / 2 = 21 ways.
So the required probability = 0.01116 * 21
= 0.2344 or 23.44%.
Answer:
Step-by-step explanation:
+x-20
use FOIL
(x - 4)(x+5)
x-4=0
x+5=0
4 and negative 5 are the factors
Okay so you want to do the parentheses first okay? So 2.3333...+1.3333333 is?3.666 or 3 2/3. So you got that right? So then 5 1/3+ 3 2/3. You get an easy 9. Because 1/3+ 2/3 adds up to 3/3, and is normally written as 1. So add a one to 5+3=8+1.
So hmmmmm, notice... the boat went up in 3hrs, came back to the starting point in 2hrs, it went up 108km, it came back, well, from 108km to distance 0, so the distance on the way back is just the same 108km
now... let's say the stream has a speed rate of "r", and the boat has a still water speed rate of "b"
bear in mind that, when the boat is going UP, is not really going "b" fast, because the stream's "r" rate is going against it, and thus subtracting "r" from "b", so is really going " b - r " fast
when the boat is going down, is not going "b" fast either, because, again the stream's rate "r" is adding to it, because is going with the current, so is really going " b + r " fast
now, recall your d =rt, distance = rate * time

solve for "r"
what's b? well, 36+ r = b