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Lesechka [4]
2 years ago
6

B is decreased by 40% and decreased again by 40%. What is the result?

Mathematics
1 answer:
skelet666 [1.2K]2 years ago
3 0

Answer:

result is 20%

Step-by-step explanation:

initially B was 100%

therefore 100% - 40%

=60% remaining

60% - 40%

= 20%

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Need some help please?
n200080 [17]

The value of the unknown length is 24

<h3>How to determine the unknown length?</h3>

Represent the unknown length with x.

So, we have the following equivalent ratio:

30 : 30 + x = 25 : 45

Express as fraction

30/30 + x = 25/45

Simplify the fraction

30/30 + x = 5/9

Cross multiply

150 + 5x = 270

Evaluate the like terms

5x = 120

Divide by 5

x = 24

Hence, the value of the unknown length is 24

Read more about similar shapes at:

brainly.com/question/24214480

#SPJ1

5 0
2 years ago
Plz help 20 pts given for the question answered
xxMikexx [17]

Answer:

what question?

Step-by-step explanation:

7 0
3 years ago
This problem has been solved!See the answerA municipal bond service has three rating categories (A, B, and C). Suppose that in t
mariarad [96]

Answer:

a. \frac{35}{51}

b. \frac{51}{100}

c. \frac{1}{5}

Step-by-step explanation:

Suppose cities represented by C', suburbs represented by S and rural represented by R,

Let x be the total number of bonds issued throughout the US,

According to the question,

n(A) = 70% of x = 0.7x,

n(B) = 10% of x = 0.1x,

n(C) = 20% of x = 0.2x,

n(A∩C') = 50% of n(A) = 0.5 × 0.7x = 0.35x,

n(A∩S) = 20% of n(A) = 0.2 × 0.7x = 0.14x,

n(A∩R) = 30% of n(A) = 0.3 × 0.7x = 0.21x,

n(B∩C') = 40% of n(B) = 0.4 × 0.1x = 0.04x,

n(B∩S) = 30% of n(B) = 0.3 × 0.1x = 0.03x,

n(B∩R) = 30% of n(B) = 0.3 × 0.1x = 0.03x,

n(C∩C') = 60% of n(C) = 0.6 × 0.2x = 0.12x,

n(C∩S) = 15% of n(C) = 0.15 × 0.2x = 0.03x,

n(C∩R) = 25% of n(C) = 0.25 × 0.2x = 0.05x,

n(C') = n(A∩C')  + n(B∩C')  + n(C∩C')  = 0.35x + 0.04x + 0.12x = 0.51x

n(S) = n(A∩S) + n(B∩S) + n(C∩S) = 0.14x + 0.03x + 0.03x = 0.20x

a. The probability that it will receive an A rating, if a new municipal bond is to be issued by a city,

P(\frac{A}{C'})=\frac{P(A\cap C')}{P(C')}=\frac{0.35x/x}{0.51x/x}=\frac{0.35}{0.51}=\frac{35}{51}

b. The proportion of municipal bonds are issued by cities = \frac{n(C')}{x}

=\frac{0.51x}{x}

=\frac{51}{100}

c. The proportion of municipal bonds are issued by suburbs = \frac{n(S)}{x}

=\frac{0.20x}{x}

=\frac{20}{100}

=\frac{1}{5}

3 0
3 years ago
Best explained and correct answer gets brainliest.
cestrela7 [59]
It'd be B) because to make a triangle the sum of two sides has to be greater than the third side. 3+4=7, and 7>5, so...<span>voilà</span>
6 0
3 years ago
6. What is the sum of the solutions?
vlada-n [284]

x * x = x^2

x * .7 = .7x

-6 * x = -6x

-6 * .7 = -4.2

x^2 + .7x - 6x -4.2

x^2 - 5.3 - 4.2

x = 6

8 0
3 years ago
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