Question

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Answer 1

The trigonometric function for an angle $\dfrac{\pi}{4}$ is

$tan\theta =1\ \ \ \ Cos \theta=\dfrac{\sqrt{2}}{2}\ \ \ \ Sin\theta = \dfrac{\sqrt{2}}{2}$

The trigonometric function for an angle $\dfrac{\pi}{6}$ will be:-

$tan\theta = \dfrac{1}{\sqrt3}}\ \ \ \ \ Sin\theta = \dfrac{1}{2} \ \ \ \ \ Cos \theta = \dfrac{\sqrt{3}}{2}$

What is trigonometry?

The branch of mathematics sets up a relationship between the sides and the angles of the right-angle triangle termed trigonometry.

The trigonometric function for an angle $\dfrac{\pi}{4}$ is

$tan\theta = tan\dfrac{\pi}{4}=1\ \ \ \ Cos \theta=Cos\dfrac{\pi}{4}=\dfrac{\sqrt{2}}{2}\ \ \ \ Sin\theta =Sin\dfrac{\pi}{4}= \dfrac{\sqrt{2}}{2}$

The trigonometric function for an angle $\dfrac{\pi}{6}$ will be:-

$tan\theta=tan \dfrac{\pi}{6}= \dfrac{1}{\sqrt3}}\ \ \ \ \ Sin\theta =Sin\dfrac{\pi}{6}= \dfrac{1}{2} \ \ \ \ \ Cos \theta = Cos\dfrac{\pi}{6}= \dfrac{\sqrt{3}}{2}$

Therefore the trigonometric function for an angle $\dfrac{\pi}{4}$ is

$tan\theta =1\ \ \ \ Cos \theta=\dfrac{\sqrt{2}}{2}\ \ \ \ Sin\theta = \dfrac{\sqrt{2}}{2}$

The trigonometric function for an angle $\dfrac{\pi}{6}$ will be:-

$tan\theta = \dfrac{1}{\sqrt3}}\ \ \ \ \ Sin\theta = \dfrac{1}{2} \ \ \ \ \ Cos \theta = \dfrac{\sqrt{3}}{2}$

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