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strojnjashka [21]
3 years ago
10

The odds that a book will be favourable reviewed by three independent critic. a b and c are 5 to 2, 4 to 3 and 3 to 4 respective

ly. what is the probability none of them are in favour of the book
​
Mathematics
1 answer:
Lelu [443]3 years ago
6 0

Answer:

1/4

Step-by-step explanation:

i think you would add 5+4+3 and 2+3+4 and divide them so 9/12 and that makes your probability  which leaves a 3/12 chance non of them are in favour of the book

You might be interested in
The length of a rectangle is 22 centimeters and the width is
nataly862011 [7]

Answer:

78cm

Step-by-step explanation:

L₁/W₁ = L₂/W₂

22/4 = L₂/6

5.5*6=L₂

L₂=33cm

Perimeter of rectangle = 2L+2W

=2(33)+2(6)

=66+12

=78cm

7 0
3 years ago
A survey among students at a certain university revealed that the number of hours spent studying the week before final exams was
Rainbow [258]

Answer:

P(25

And we can find this probability with this difference:

P(0

And in order to find these probabilities we can use tables for the normal standard distribution, excel or a calculator.  

P(0

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem'

Let X the random variable that represent the hous spent studying the week before final exams of a population, and for this case we know the distribution for X is given by:

X \sim N(25,6)  

Where \mu=25 and \sigma=6

We are interested on this probability

P(25

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(25

And we can find this probability with this difference:

P(0

And in order to find these probabilities we can use tables for the normal standard distribution, excel or a calculator.  

P(0

6 0
3 years ago
Most dermatologists recommend using sunscreens that have a Sun Protection Factor (SPF) of at least 30. One of the authors wanted
Basile [38]

Answer:  We are 95% confident that the mean SPF level of sunscreen used by all Cal Poly students is between 29.0813 and 40.0187.

Step-by-step explanation:

Given : Significance level : \alpha: 1-0.95=0.05

Sample size : n= 52 , which is a large sample (n>30), so we use z-test.

By using z-value table,

Critical value: z_{\alpha/2}=1.96

Sample mean : \overline{x}= 34.55

Standard deviation : \sigma= 20.12

The confidence interval for population means is given by :-

\overline{x}\pm z_{\alpha/2}\dfrac{\sigma}{\sqrt{n}}

i.e. 34.55\pm(1.96)\dfrac{ 20.12}{\sqrt{52}}

=34.55\pm5.46867829455\\\\\approx34.55\pm5.4687\\\\=(34.55-5.4687, 34.55+5.4687)=(29.0813,\ 40.0187)

Now, the 95% confidence interval for the ppopulation mean = . (29.0813, 40.0187)

Hence, We are 95% confident that the mean SPF level of sunscreen used by all Cal Poly students is between 29.0813 and 40.0187.

7 0
3 years ago
Please help I will mark you as brainliest
Vilka [71]

Answer:

3999

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
What should be the right answer for this question
xxTIMURxx [149]

Answer:

3cm

Step-by-step explanation:

cb is the same length bisector ac, so the answer is <u>3 cm</u>

3 0
3 years ago
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